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3 years ago

The difference between 4,632 and 20,000 is what number

2 answers:

7 0

Difference means to minus which will get our difference.

4632 - 20000 = <span>-15368

SO 4632 - 20000 is equal to negative(</span>-)15368 (<span>-15368</span>)

Hope i helped ya!!!!!!!☺☺

77julia77 [94]3 years ago

4 0

When finding the difference between you will need to subtract. So lets subtract
4632-20000
And you get -15368.
So the differences between 4,632 and 20,000 is -15368

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Which equation is equivalent to log Subscript 3 Baseline (x 5) = 2?.

grin007 [14]

The equivalent equation is x - 4 = 0.

<h2>Linear system</h2>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

<h3>Simplification</h3>

Simplification is to make something easier to do or understand and to make something less complicated.

Given

The expression is $\rm log_3(x + 5) = 2$ .

The equivalent equation.

<h3>How to find the equivalent equation.</h3>

The expression is $\rm log_3(x + 5) = 2$ .

On simplifying. we get

$\begin{aligned} \rm log_3(x + 5) &= 2\\x + 5 &= 3^2\\x + 5 &= 9 \\x &= 9 - 5\\x &= 4\\x - 4 &= 0\\\end{aligned}$

The equivalent equation is x - 4 = 0.

More about the linear system link is given below.

brainly.com/question/20379472

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2 years ago

Eighteen cement squares cover a patio with an area of 40.5m^2. What is the side length of one of the squares

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2 years ago

3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a <em>normal distribution </em>with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so <u>X when Z = -0.253</u>.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so <u>X when Z = 1.28</u>.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so <u>X when Z = -0.675</u>.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so <u>X when Z = 0.675</u>.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

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Find the common factor of all the terms of the polynomial 16x2 - 14x. A. 4x² B. 2x² c. 4x D. 2x

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Common factor would be D. 2x

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2 years ago

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25 2/5= $\frac{23*5+2}{5}= \frac{117}{5}$

and now we multiply it by 1/3:

$\frac{1}{3}\frac{117}{5}=\frac{39}{5}=7\frac{4}{5}$

and that's the answer: the basketball equipment weights 7 4/5 pounds.

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2 years ago