Answer is -23
Add 4 from both sides
Subtract 5 from both sides
Then divide 7
Answer:
no it cannot
Step-by-step explanation:
becuase of many reasons
Answer:
The probability of friend A winning with HH = 1/4.
Step-by-step explanation:
The probability of an event, A is P(A) given by the relationship;
P(A) = (The number of required outcome)/(The number of possible outcomes)
The parameters given are;
The condition of friend A winning = Coin toss sequence HH shows up
The condition of friend B winning = Coin toss sequence TH shows up
The number of possible outcomes = TT, TH, HH, HT = 4
(TH and HT are taken as different for the game to be fair)
The number of required outcome = HH = 1
Therefore;
The probability of friend A winning with HH = 1/4.
Answer:
1. Yes
2. Exactly Double
Hope this helps and have a great day :)
Step-by-step explanation:
