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3 years ago

14

Pls help hw came late and i dont want a detention

2 answers:

kogti [31]3 years ago

8 0

Answer:

A) 108

B) C virtical opisite angles

Step-by-step explanation:

Mrac [35]3 years ago

4 0

Answer:

180

Step-by-step explanation:

they are vertical angles

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Help pls!<br> simplify<br> -6 x^{2} ÷ 12 - 2(-7)<br><br> a. -17<br> b. 35<br> c. -35<br> d. 11

Mariana [72]

Answer:

11

Step-by-step explanation:

Given: $\frac{-6^{2}}{12} -2(-7)$

Using PEDMAS rule to solve it.

Now, simplifying:

We first open parenthesis which is (-7) = -7

= $\frac{-6^2}{12}-2\times -7$

Now, we evaluate the exponent which is $-6^2=-36$

Next, we divide -36 by 12 to get -3

= $\frac{-36}{12}-2\times -7 \\= -3 -2\times -7$

Next, we multiply -2 and -7 to get 14

= $-3 + 14$

Lastly, we add -3 and 14 to get 11

= $11$

∴ Answer is 11

5 0

3 years ago

Marking brainliest <br><br> Can someone tell me why animal testing is bad?

daser333 [38]

Answer:

because they inject it into the animals eye's

5 0

3 years ago

Read 2 more answers

I have no idea what 6/x = 8/19 is help bruv

bazaltina [42]

Answer: X=17

Step-by-step explanation: (sorry if im wrong) so basicly X would be 17 because 6+2=8 so X has to +2 to get to 19 making X=17

8 0

3 years ago

Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

7 0

3 years ago

Darlene was asked to identify which of the following numbers is prime. Witch number should she choose

nordsb [41]

3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191 those are some prime numbers :)

5 0

3 years ago