I think b is 106 I really hope this helps I’m sorry if it doesn’t
$10.50... multiply each quantity by .35cnts...$24.50-$14.00=$10.50
<span>Say the code only needed to be one number long. Going from 0-9, there are ten digits. Therefore, there are ten unique codes.
Now say the code has to be two numbers long. There are ten possibilities
for the first digit, 0-9. But the second digit only has nine
possibilities, since each number has to be different. (The first number
might be 0, so the second can only go from 1-9) For each of the first
ten possibilities, there are nine possibilities for the second. We
multiply those two numbers together, 10 * 9, and we get 90.
Now we just extend the logic. The third number only has eight
possibilities, while the fourth number only has seven. 10 * 9 * 8 * 7 =
5040 possible codes. I hope this helped! has a great day! :)</span>
Answer:
12 floors
Step-by-step explanation:
768 ÷ 64 = 12.
The e vertex of the decagon will be in the top position after rotating it counterclockwise by 3 times the smallest angle of rotation.
Which vertex will be in the top position of the regular decagon?
A regular decagon has 10 sides of equal lengths with points labeled 'a' through 'j' clockwise. It is given that the point a is the top-left point. Hence, the the vertex which is in the the top position currently is 'b'.
Now, the smallest angle of rotation will be the angle between the two sides of the decagon.
In the first rotation by the smallest angle in counterclockwise direction, point 'c' will come to the top position. In the second rotation by the smallest angle in counterclockwise direction, point 'd' point will become the top most vertex. Finally, after the third similar rotation, 'e' vertex will be in the top position of the decagon. (Refer the attached diagram)
Learn more about decagon here:
brainly.com/question/27314677
#SPJ4