There are two questions about consecutive odd integers
1) (x + 2)
2) The numbers are 19 and 21
1) We have two consecutive odd integers.
Remember that the distance between any two consecutive odd numbers is 2.
5 - 3 = 2
7 - 5 = 2
13 - 11 = 2
etc.
So if the smaller of the two odd numbers is x, then the larger one will be (x + 2).
2) We have two consecutive odd numbers, let's write them as:
(2*n + 1) and (2*n + 3)
Where n is an integer number.
We know that the smaller one is 12 more than one third of the larger one, so we have:
(2*n + 1) = 12 + (2*n + 3)/3
Now we can solve this for n
2*n + 1 = 12 + (2/3)*n + 1
2*n - (2/3)*n = 12 + 1 - 1
(4/3)*n = 12
n = (3/4)*12 = 9
n = 9
Then the two consecutive odd integers are:
(2*n + 1) = (2*9 + 1) = 19
(2*n + 3) = (2*9 + 3) = 21
If you want to learn more, you can read:
brainly.com/question/15453368
