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Phantasy [73]
3 years ago
12

At what value of x does the graph of the following function f(x) have a vertical asymptote? f(x)=1/x+3

Mathematics
2 answers:
Snezhnost [94]3 years ago
8 0
The right answer is D
ratelena [41]3 years ago
5 0

Answer:

d

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 ⇒ x = - 3 ← equation of vertical asymptote

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4 0
3 years ago
Can someone please explain number 6 to me ! :((
Mazyrski [523]

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8 0
3 years ago
The figure shows a triangle with an angle bisector. If angle SUT= 34°, find the measurement of angle 1?
Burka [1]

The ANGLE BISECTOR mentioned in the problem is simply just a line that separates an angle in half.

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Therefore ∠1 is just one-half of the ∠SUT.

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8 0
1 year ago
Find the value of x please help
____ [38]

using angle sum property

we get

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(x+12)=180-145

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x= 35-12

x= 23

3 0
2 years ago
Read 2 more answers
Are the quadrilaterals similar? If so, give the scale factor. If not, explain.
castortr0y [4]
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