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3 years ago

At what value of x does the graph of the following function f(x) have a vertical asymptote? f(x)=1/x+3

Mathematics

2 answers:

Snezhnost [94]3 years ago

8 0

The right answer is D

ratelena [41]3 years ago

5 0

Answer:

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 ⇒ x = - 3 ← equation of vertical asymptote

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sleet_krkn [62]

$\bold{Hey\ there!}$

$\bold{Assuming,\ you\ meant: -5(-2)^4}$

$\bold{If\ so\ follow\ these\ steps\downarrow}$
$\bold{(-2)^4=16}$
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$\boxed{\boxed{\bold {Thus,\ your\ answer\ is: -80}}}\checkmark$

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