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3 years ago

At what value of x does the graph of the following function f(x) have a vertical asymptote? f(x)=1/x+3

Mathematics

2 answers:

Snezhnost [94]3 years ago

8 0

The right answer is D

ratelena [41]3 years ago

5 0

Answer:

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 ⇒ x = - 3 ← equation of vertical asymptote

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3 years ago

Can someone please explain number 6 to me ! :((

Mazyrski [523]

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3 years ago

The figure shows a triangle with an angle bisector. If angle SUT= 34°, find the measurement of angle 1?

Burka [1]

The ANGLE BISECTOR mentioned in the problem is simply just a line that separates an angle in half.

Meaning if it bisects ∠SUT which is 34. It just means that it divides the angle 34 into 2 equal parts.

Therefore ∠1 is just one-half of the ∠SUT.

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8 0

1 year ago

Find the value of x please help

____ [38]

using angle sum property

we get

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x= 23

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2 years ago

Read 2 more answers

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castortr0y [4]

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