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Tamiku [17]
3 years ago
8

Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has

coordinates of (3, –5), which point lies on a side of the pre-image, square RSTU?
A.(–5, –3)
B.(3, –3)
C.(–1, –6)
D.(4, –9)???????????????

Mathematics
2 answers:
MrMuchimi3 years ago
8 0

The answer to this question is C

zalisa [80]3 years ago
6 0

Step 1

<u>Find the rule of the translation of the pre-image to the image</u>

we know that

the point S has coordinates of ((3,-5)

the point S' has coordinates of ((-4,1)

so

a) the rule of the translation of the pre-image to the image is

(x,y)------> (x-7,y+6)

Step 2

<u>Find the rule of the translation of the image to the pre-image</u>

a) the inverse rule of the translation of the image to the pre-image is

(x',y')------> (x'+7,y'-6)

Step 3

<u>Find the coordinates of the vertices of the pre-image</u>

Applying the inverse rule of the translation of the image to the pre-image

a) Point R'(-8,1)

R(-8+7,1-6)=R(-1,-5)

b) Point T'(-4,-3)

T(-4+7,-3-6)=T(3,-9)

c) Point U'(-8,-3)

U(-8+7,-3-6)=U(-1,-9)

Step 4

Using a graphing tool

graph the points of the pre-image and the points A,B,C and D to determine the solution of the problem

we have

R(-1,-5) \\S(3,-5)\\T(3,-9)\\U(-1,-9)\\ \\A(-5,-3)\\B(3,-3)\\C(-1,-6)\\D(4,-9)

see the attached figure        

therefore        

<u>the answer is the option </u>

C(-1,-6)


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