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Tamiku [17]
2 years ago
8

Square RSTU is translated to form R'S'T'U', which has vertices R'(–8, 1), S'(–4, 1), T'(–4, –3), and U'(–8, –3). If point S has

coordinates of (3, –5), which point lies on a side of the pre-image, square RSTU?
A.(–5, –3)
B.(3, –3)
C.(–1, –6)
D.(4, –9)???????????????

Mathematics
2 answers:
MrMuchimi2 years ago
8 0

The answer to this question is C

zalisa [80]2 years ago
6 0

Step 1

<u>Find the rule of the translation of the pre-image to the image</u>

we know that

the point S has coordinates of ((3,-5)

the point S' has coordinates of ((-4,1)

so

a) the rule of the translation of the pre-image to the image is

(x,y)------> (x-7,y+6)

Step 2

<u>Find the rule of the translation of the image to the pre-image</u>

a) the inverse rule of the translation of the image to the pre-image is

(x',y')------> (x'+7,y'-6)

Step 3

<u>Find the coordinates of the vertices of the pre-image</u>

Applying the inverse rule of the translation of the image to the pre-image

a) Point R'(-8,1)

R(-8+7,1-6)=R(-1,-5)

b) Point T'(-4,-3)

T(-4+7,-3-6)=T(3,-9)

c) Point U'(-8,-3)

U(-8+7,-3-6)=U(-1,-9)

Step 4

Using a graphing tool

graph the points of the pre-image and the points A,B,C and D to determine the solution of the problem

we have

R(-1,-5) \\S(3,-5)\\T(3,-9)\\U(-1,-9)\\ \\A(-5,-3)\\B(3,-3)\\C(-1,-6)\\D(4,-9)

see the attached figure        

therefore        

<u>the answer is the option </u>

C(-1,-6)


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Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a
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Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, \sin x and \cos x are defined for all real numbers.

\tan x=\frac{\sin x}{\cos (x)}, this function is not defined where \cos x=0.

\cot x=\frac{\cos x}{\sin (x)}, this function is not defined where \sin x=0.

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For option A

The domain of f(x)=\sin(x) is all real numbers.

The domain of g(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

For option B

The domain of f(x)=\cos(x) is all real numbers.

The domain of f(x) =csc(x) is x\ne n\pi

For option C,

The domain of G(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

The domain of f(x) =cot(x) is x\ne n\pi

For option D;

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3 0
3 years ago
Read 2 more answers
Please help as soon as possible 50 points
Morgarella [4.7K]

Answer:

the answer is d. 4x²+x-6

Step-by-step explanation:

In order to combine the fractions, they need to have the same denominator.

So, multiply each of their numerators by the denominator they need to be equivalent.

This would look like this:

3x/x+3 --> 3x(x)/x(x+3)        ---simplify this as--> 3x²/x(x+3)

x-2/x  --> (x-2)(x+3)/x(x+3)  ---simplify this as --> x²+x - 6/x(x+3)

3x                    3x(x)                                     x-2                   (x-2)(x+3)

-----      --->        -----                 and             --------   --->           ---------

x+3                   x(x+3)                                    x                        x(x+3)

now that both fractions have the same denominator, we can add their numerators.

3x² + x²+x-6 = 4x²+x -6

This should now look like this:

4x²+x -6

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x(x+3)

8 0
2 years ago
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Mancini's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is what
Citrus2011 [14]

<em>The complete exercise with the answer options is as follows:</em>

Mancini's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is what he found.

Type of Crust Number Sold

Thin crust            364

Thick crust             240

Stuffed crust             176

Pan style            260

Based on this information, of the next 3000 pizzas he sells, how many should he expect to be thick crust? Round your answer to the nearest whole number. Do not round any intermediate calculations.

Answer:

692 thick crust pizzas

Step-by-step explanation:

With the data given in the exercise, we must first find the total number of pizzas, then we must find the proportion between the thick crust pizzas and the total number of pizzas, finally we must propose a rule of three to find the new proportion of crust pizzas thick on a total of 3000 pizzas.

Type of Crust Number Sold

Thin crust            364

Thick crust             240

Stuffed crust             176

Pan style            260

total pizzas  : 1040

Now we must calculate for 3000 pizzas how much would be the total of thick crust pizzas.For that we must use the relationship found, that is, in 1040 pizzas there are 240 thick crust pizzas

1040→240

3000→x

x= \frac{3000x240}{1040} = 692

Now we have a new proportion that out of 3000 pizzas there are a total of 692 thick crust pizzas

3 0
3 years ago
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