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3 years ago

10

Tu amigo está a 55 metros de la base de un árbol y el ángulo de elevación 3 desde donde está parado en el suelo hasta la copa de

ese árbol es de 50 grados. ¿Cuanto mide el árbol al metro más cercano?

1 answer:

castortr0y [4]3 years ago

8 0

Step-by-step explanation:

Ummm D

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Following are the solution to the given point:

Step-by-step explanation:

Please find the comp[lete question in the attached file.

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$\bold{ \lim_{n \to \ \infty} (1+ \frac{r}{n})^{nt} =e^{rt}}$

In point 1:

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In point 2:

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In point 3:

Its key thing to understand, which would be that you consider the limit n to $\infty$ , in which r and t were constants!

$=lim_{n \to \ \infty} \ln (y) = lim_{n \to \ \infty} nt \ln(1+\frac{r}{n})\\\\= lim_{n \to \ \infty} \frac{\ln(1+\frac{r}{n})}{\frac{1}{nt}}\\\\= lim_{n \to \ \infty} \frac{\frac{-r}{\frac{n^2}{(1+\frac{r}{n})}}}{- \frac{1}{n^2t}}\\\\= lim_{n \to \ \infty} \frac{\frac{rn^2t}{n^2}}{(1+\frac{r}{n})}\\\\= lim_{n \to \ \infty} \frac{rt}{(1+\frac{r}{n})}\\\\= \frac{rt}{(1+\frac{r}{0})}\\\\=rt$

In point 4:

$\to \lim_{n \to \ \infty} = (1+\frac{r}{n})^{nt}$ and

$\to \lim_{n \to \ \infty} = A_0e^{rt}$

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3 years ago