All categories

3 years ago

Pls telll/pls tell pls tell pls tell

Mathematics

1 answer:

grandymaker [24]3 years ago

7 0

Answer: 2

Step-by-step explanation:

Given

The polynomial is $x^4+x^3-2x^2+x+1$ is divided by $x-1$

According to the remainder theroem

$\Rightarrow x-1=0\\\Rightarrow x=1$

Put $x=1$ in the polynomial to get the remainder

$\Rightarrow 1+1-2+1+1\\\Rightarrow 2$

So, we get the remainder 2.

You might be interested in

Part A. Dario purchased a party size sub, and he decides to share it with three of his friends. so he cuts the sub into four equ

wel

Answer: 4/6 = 2/32/3 = 2/3

Step-by-step explanation: hope this help

3 0

3 years ago

The following shows the monthly sales in units of six salespersons before and after a bonus plan was introduced. At 95% confiden

saw5 [17]

Answer:

it is clear that at 95% confidence that the bonus plan has increased the sales significantly, because if we observe you will notice that sales after is greater than sales before in all six cases.

Step-by-step explanation:

A 95% confidence interval as we have above is the range of values that we can say with utmost certainty and confidence that 95% chance it contains the true mean of the population. in other words we can say that a 95% confidence interval defines a range of values that you can be 95% certain contains the population mean.

4 0

3 years ago

Given two linear equations: y=-2x+5 and y=1/2x-2. Select all or one that apply.

Rudiy27

The answer would be Perpendicular.

8 0

4 years ago

Find the circumference of the circle. Use pi=3.14

Dmitrij [34]

To solve this, you need to know the formula to find the circumference of the circle. It is: C=2(pie)r.

C is what you are finding.
Pie is 3.14(you already got that).
R is the radius.

There is not enough information to solve your problem, but I hoped the equation helped!

6 0

4 years ago

Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has

RUDIKE [14]

Answer:

FLAW TYPE2 NO TYPE2 FLAW

TYPE1 0.015 0.025

NO TYPE1 FLAW 0.01 0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw) = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) = p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) = 0.025 - 0.015 = 0.01

THEREFORE the Bivariate Table;

FLAW TYPE2 NO TYPE2 FLAW

TYPE1 0.015 0.025

NO TYPE1 FLAW 0.01 0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3) probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw) = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) = p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% = 0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

5 0

4 years ago