In the diagram, m Find m

2 answers:

8 0

Find the slope, m, of the line whose graph contains the points (1,2) and (2, 7). ... What does it mean if the slope, m, is negative in y = mx + b?

frutty [35]3 years ago

6 0

Step-by-step explanation:

where is the diagram first you have to show figure then I will find m

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What makes a pair linear?

zavuch27 [327]

Answer:

A linear pair of angles is formed when two lines intersect. Two angles are said to be linear if they are adjacent angles formed by two intersecting lines. The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

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3 years ago

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Your friend says that the absolute value equation | 3x+8 |-9=-5 has no solution because the constant

sineoko [7]

Answer:

Incorrect

Step-by-step explanation:

We are given the equation:

$\displaystyle \large{|3x+8|-9=-5}$

Add both sides by 9.

$\displaystyle \large{|3x+8|-9 + 9=-5 + 9} \\ \displaystyle \large{|3x+8|=4}$

When we want to tell if the absolute equation has solutions or not, we have to simplify in this form first: or isolate the absolute sign.

$\displaystyle \large{ |ax + b| = c}$

If c ≥ 0, the equation has solutions.

If c < 0, the equation does not have solutions.

Therefore, it does not always matter if the constant on right side is in negative because if there is a number on the left side then there is a chance that the equation has solutions.

From |3x+8| = 4 is equivalent |3x+8|-9=-5 and the right side is 4 which is positive.

Hence, the equation does have a solution!

3 0

3 years ago

The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.

Scrat [10]

Just did a specific one of these; let's do the general case.

The point nearest the origin is (a,b).

The line from the origin through the point is

$bx - ay = 0$

The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):

$ax + by = a^2 + b^2$