In a freshman class of 80 students,22 students take Consumer Education,20 students take French,and 4 students take both.Which eq uation can be used to find the probability,P, that a randomly selected student from this class takes Consumer Education, French,or both? A: P = 11/40 + 1/4 + 1/20 B: P = 11/40 + 1/4 C: P = 11/40 + 1/4 - 1/20 D: P = 11/40 + 1/4 - 1/10
1 answer:
<h3>
Answer: Choice C </h3>
P = 11/40 + 1/4 - 1/20
=========================================================
Explanation:
The formula we use is
P(A or B) = P(A) + P(B) - P(A and B)
In this case,
P(A) = 22/80 = 11/40 = probability of picking someone from consumer education P(B) = 20/80 = 1/4 = probability of picking someone taking French P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes So,
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 11/40 + 1/4 - 1/20
which is why choice C is the answer
----------------
Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.
You might be interested in
Answer:
8x15x12=1440
Step-by-step explanation:
Answer:
2, and 5
Step-by-step explanation:
. V = B( h )
. V = (pi) (r squared) (h)
Answer:
48 inches
Step-by-step explanation:
Answer:
15/9 :))
is your answerrr