F(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x = 2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144
D(-1,-1), E(-8,-4), F(-8,-8)
9514 1404 393
Answer:
AE = CE = 23; BE = DE = 20
Step-by-step explanation:
Put the values of the variables in their place and do the arithmetic.
AE = 2u+5 = 2(9) +5 = 23
BE = 6v-1 = 6(3.5) -1 = 20
CE = 3u-4 = 3(9) -4 = 23
DE = 8v-8 = 8(3.5) -8 = 20
The diagonals cross at their midpoints, so the quadrilateral is a parallelogram.
