We can write a proportion. We know that $50 is the original value and $80 is the marked up price. We don't know the marked up percentage. Let's call it x. We write equal ratios of $\frac{x}{100}$ comparing percent and $\frac{50}{80}$ comparing the 50 to the marked up price. We then set them equal.

$\frac{x}{100} =\frac{50}{80}$

We then cross multiply across the equal sign from numerator to the opposite numerator.

80(x)=50(100)

80x=5000

We divide to find x.

x=62.5

This means the bicycles are marked up 62.5% and the original value is 37.5%.

8 0

3 years ago

Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb

Irina18 [472]

Given 2.50x + 3.50y < 30.

Where x represent the number of hamburgers and y represent the number of cheeseburgers.

Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.

So, first step is to plug in y=4 in the given inequality. So,

2.50x+3.50(4)<30

2.50x+14 <30

2.50x<30- 14 Subtracting 14 from each sides.

2.50x< 16

$\frac{2.50x}{2.50}$ Dividing each sides by 2.50.

x<6.4

Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,

thus x = 6 hamburgers

So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15

Hope this helps!!

8 0

2 years ago