The domain of both functions will be ?

Mathematics

1 answer:

Tju [1.3M]3 years ago

5 0

C !!! Hope it helped :)

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Solve the equation for y 4x+7y=28 y=

bogdanovich [222]

Let's solve for y.

4x+7y=28

Add -4x to both sides.

4x+7y+−4x=28+−4x

7y=−4x+28

Divide both sides by 7.

7y/7=−4x+28/7

y=−4/7x+4

5 0

4 years ago

3/4x + 2x - 3= -1/4 + 21

Lesechka [4]

x = 95/11 lmk if it’s wrong.

5 0

3 years ago

Please help anybody! shoutout to

kirza4 [7]

Answer:

1/4 or 25%

Step-by-step explanation:

Only 1 whisker earned 25 or less so it's 1/4

6 0

3 years ago

Read 2 more answers

Expand the binomial (2x+5)^5

Whitepunk [10]

That would simplify to 32x^5+400x^4+200x^3+5000x^2+6250x+3125
You would do that because you have to write it repeatedly as (2x+5)(2x+5) and so on.

3 0

4 years ago

Point m is the midpoint of kL. M(1,-1) and L(8,-7. What are the coordinates of point k?

Phoenix [80]

Answer: (-6, 5)

Step-by-step explanation:

Use the Midpoint Formula: $\dfrac{(x_k, y_k)+(x_L,y_L)}{2}=(x_m, y_m)$

Separate the x's and y's and solve them individually:

$\dfrac{x_k+x_L}{2}=x_m\qquad \qquad \qquad \qquad\dfrac{y_k+y_L}{2}=y_m\\\\\\\dfrac{x_k+8}{2}=1\qquad \qquad \qquad \qquad \qquad \dfrac{y_k-7}{2}=-1\\\\\\x_k+8=2\qquad \qquad \qquad \qquad \qquad y_k-7=-2\\\\\\x_k\quad =-6 \qquad \qquad \qquad \qquad \qquad y_k\qquad =5$

So, the k-coordinate is (-6, 5)

3 0

3 years ago