For this case we propose a system of equations:
x: Let the variable representing the age of the first child of the Smiths
y: Let the variable representing the age of the second child of the Smiths
According to the data of the statement we have to:
![x + y = 23\\x * y = 132](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%2023%5C%5Cx%20%2A%20y%20%3D%20132)
From the first equation we have to:
![x = 23-y](https://tex.z-dn.net/?f=x%20%3D%2023-y)
We substitute in the second equation:
![(23-y) * y = 132\\23y-y ^ 2 = 132\\y ^ 2-23y + 132 = 0](https://tex.z-dn.net/?f=%2823-y%29%20%2A%20y%20%3D%20132%5C%5C23y-y%20%5E%202%20%3D%20132%5C%5Cy%20%5E%202-23y%20%2B%20132%20%3D%200)
We find the solutions by factoring:
We look for two numbers that, when multiplied, result in 132 and when added, result in 23. These numbers are 11 and 12.
Thus, we have that the factorized equation is:
![(y-11) (y-12) = 0](https://tex.z-dn.net/?f=%28y-11%29%20%28y-12%29%20%3D%200)
Thus, the solutions are:![y_ {1} = 11\\y_ {2} = 12](https://tex.z-dn.net/?f=y_%20%7B1%7D%20%3D%2011%5C%5Cy_%20%7B2%7D%20%3D%2012)
So, we can take any of the solutions:
With ![y = 11](https://tex.z-dn.net/?f=y%20%3D%2011)
Then![x = 23-11 = 12](https://tex.z-dn.net/?f=x%20%3D%2023-11%20%3D%2012)
Therefore, the ages of the children are 11 and 12 respectively.
Answer:
The ages of the children are 11 and 12 respectively.