2 years ago

Find the total surface area of this cuboid.

Mathematics

1 answer:

makkiz [27]2 years ago

6 0

Answer:

120cm

Step-by-step explanation:

it 120 cm because of length×with×hight

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Alexeev081 [22]

2x(-5x-3)

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3 years ago

If 1 inch = 50 miles how many miles is 8.5 in

GenaCL600 [577]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ 8.5 in = 425 miles

If 1 mi = 50 inches, multiply by 8.5:

50 x 8.5 = 425

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3 years ago

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Crazy boy [7]

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3 years ago

19. INSECTS An average aunt is 1/4 inch long. An average aphid is 3/32 inch long. How many times longer is an average and then a

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3 years ago

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = 4x and y = x2/4 . Find V by slicin

aliya0001 [1]

Answer:

Step-by-step explanation:

Consider the graphs of the $y = 4x$ and $y = \frac{x^{2} }{4}$ .

By equating the expressions, the intersection points of the graphs can be found and in this way delimit the area that will rotate around the Y axis.

$4x = \frac{x^{2} }{4} \\ x^{2} = 16x \\ x^{2} - 16x = 0 \\ x(x-16) = 0$ then $x=0$ o $x=16$ . Therefore the integration limits are:

$y = 4(0) = 0$ and $y = 4(16) = 64$

The inverse functions are given by:

$x = 2 \sqrt{y}$ and $x = \frac{y}{4}$ . Then

The volume of the solid of revolution is given by:

$\int\limits^{64}_ {0} \, [2\sqrt{y} - \frac{y}{4}]^{2} dy = \int\limits^{64}_ {0} \, [4y - y^{3/2} + \frac{y^{2}}{16} ]\ dy = [2y^{2} - \frac{2}{5}y^{5/2} + \frac{y^{3}}{48} ]\limits^{64}_ {0} = 546.133 u^{2}$

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3 years ago