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Bumek [7]
3 years ago
13

You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You disc

over that the balloon bursts when you have pitched it to a height of 11 m. With what velocity did the balloon hit the ground? The acceleration of gravity is 9.8 m/s^2. The positive direction is up, so the velocity when it hits is negative.
Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

v=-1.46 \ m/s

Step-by-step explanation:

So, as balloon reaches its maximum height i.e. 11 m , its velocity become 0.

Therefore, v_{top}=0 \ m/s.

It is given that acceleration due to gravity should be taken as , g=-9.8 \ m/s^2.(because it direction is down)

Now it is also given that upward direction is positive and downward direction is negative. So velocity should be negative.

Using equation of motion,

v_{final}^2 - v_{initial}^2 =2\times a\times displacement   .....eqn 1.

where , displacement = -11 m(because it displace towards down) and a=g=-9.8\ m/s^2

Putting these values in eqn 1 .

v_{final}^2-0^2 =2\times 9.8 \times 11

v = \pm1.46 m/s.

But as we know direction of velocity is downward.

Therefore, v=-1.46 \ m/s

where negative sign indicates its direction is downward.

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