Answer: bro Idk imma try to figure it out
Step-by-step explanation:
Step-by-step explanation:
Given sequence is: 2,5,8,11,14
Here first term a = 2
Common Difference d = 3
![\because \: t_n = a +(n-1) d \\ \\ \therefore \: t_n = 2+(n-1) 3 \\ \\ \therefore \: t_n = 2+3n- 3 \\ \\ \huge \purple{ \boxed{\therefore \: t_n = 3n- 1}} \\ is \: the \: required \: explicit \: formula\\](https://tex.z-dn.net/?f=%5Cbecause%20%5C%3A%20%20t_n%20%3D%20a%20%2B%28n-1%29%20d%20%5C%5C%20%20%5C%5C%20%20%5Ctherefore%20%5C%3A%20t_n%20%3D%202%2B%28n-1%29%203%20%5C%5C%20%20%5C%5C%20%5Ctherefore%20%5C%3A%20t_n%20%3D%202%2B3n-%203%20%5C%5C%20%20%5C%5C%20%20%5Chuge%20%5Cpurple%7B%20%5Cboxed%7B%5Ctherefore%20%5C%3A%20t_n%20%3D%203n-%201%7D%7D%20%5C%5C%20%20is%20%5C%3A%20the%20%5C%3A%20required%20%5C%3A%20explicit%20%5C%3A%20formula%5C%5C%20)
Perpendicular slope: 3
y + 7 = 3(x + 3)
y + 7 = 3x + 9
y = 3x + 2
Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get
![x=18.25](https://tex.z-dn.net/?f=x%3D18.25)
![y=13.25](https://tex.z-dn.net/?f=y%3D13.25)
Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
Answer:
2m
Step-by-step explanation:
(m+3) (m-1)
We need to FOIL
first m*m = m^2
outer -1*m = -m
inner = 3m
last 3*-1 = -3
Add these together
m^2 -m +3m -3
m^2 +2m -3