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Oksanka [162]
3 years ago
10

Eli and Samantha work at a dry cleaners ironing shirts. Eli can iron 20 shirts per hour, and Samantha can iron 35 shirts per hou

r. Samantha worked 2 more hours than Eli and they ironed 400 shirts between them. Write a system of equations that could be used to determine the number of hours Eli worked and the number of hours Samantha worked. Define the variables that you use to write the system
Mathematics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

see the explanation

Step-by-step explanation:

Let

x ----> the number of hours Eli worked

y ----> the number of hours Samantha worked

we know that

Eli and they ironed 400 shirts between them

so

20x+35y=400 -----> equation A

Samantha worked 2 more hours than Eli

so

y=x+2 ----> equation B

solve the system by substitution

substitute equation B in equation A

20x+35(x+2)=400

solve for x

20x+35x+70=400\\55x=330\\x=6

Find the value of y

substitute the value of x in equation B

y=6+2=8

therefore

The number of hours Eli worked was 6 and the number of hours Samantha worked was 8

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dangina [55]

Answer:

Problem 1:

a. x=2

b. x=3

c. x=1

Problem 2:

A multiplication equation to hold the table true:

18\times3=54

A division equation to hold the table true:

\frac{54}{3} =18

Step-by-step explanation:

Given in problem 1:

(a). The equation is \frac{x}{6} > 1

It holds true for all values of x> 6.

Let us say x=12,

\frac{x}{6}=\frac{12}{6}  =2 which is greater than 1.

(b). The equation is \frac{x}{6} < 1

It holds true for all values of x< 6.

Let us say x=3

\frac{x}{6} =\frac{3}{6} =\frac{1}{2} which is less than 1.

(c). The equation is \frac{x}{6} = 1

It holds true for only x= 6.

Let us say x=6,

\frac{x}{6} =\frac{6}{6}=1 which is equal to 1.

Problem 2:

A multiplication equation to hold the table true:

18\times3=54

A division equation to hold the table true:

\frac{54}{3} =18

Therefore these are the values which hold true to the equation in problem 1 and 2.

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3 years ago
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Answer:

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Step-by-step explanation:

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