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3 years ago

How do I find the percent of 60% of 40

Mathematics

2 answers:

emmainna [20.7K]3 years ago

8 0

Answer:24

Step-by-step explanation:

40% 60 is just 0.4⋅60=24

tino4ka555 [31]3 years ago

5 0

Answer: turn percentages into decimals then multiply that by the initial number

Step-by-step explanation:

60%

0.60

0.60*40= 24

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Suppose the method of tree ring dating gave the following dates A.D. for an archaeological excavation site. Please show your wor

natita [175]

Answer:

a) $\bar X=\frac{1245+1245+1321+1191+1295+1330+1239+1250+1228}{9}= 1260.444$

b) $s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got:

$s = 45.580$

c) For this case since the sampel size is n=9 <30 we can use the t distribution in order to find the confidence interval.

d) $1260.444-2.306 \frac{45.580}{\sqrt{9}}= 1225.408$

$1260.444+2.306 \frac{45.580}{\sqrt{9}}= 1295.480$

Step-by-step explanation:

For this case we ave the following data:

1245 1245 1321 1191 1295 1330 1239 1250 1228

Part a

We can calculate the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X= \frac{1245+1245+1321+1191+1295+1330+1239+1250+1228}{9}= 1260.444$

Part b

For this case we can use the following formula in order to find the sample standard deviation:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got:

$s = 45.580$

Part c

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

For this case since the sampel size is n=9 <30 we can use the t distribution in order to find the confidence interval.

Part d

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom given by:

$df = n-1 = 9-1=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=2.306$

Now we have everything in order to replace into formula (1):

$1260.444-2.306 \frac{45.580}{\sqrt{9}}= 1225.408$

$1260.444+2.306 \frac{45.580}{\sqrt{9}}= 1295.480$

8 0

4 years ago

What is the value of k that makes the equation (4x^2y^2+5xy+k)+(kx^2y^2-2xy-6)=7x^2+kxy-3

Fofino [41]

Answer:

k=<u>7x^(2)-4x^(2)y^(2)-3xy+3</u>

x^(2)y^(2)-xy

pretend the underline is like the line for a fraction/ division

Step-by-step explanation:

5 0

3 years ago

Why is 2x 3/4 less than 2?

Kipish [7]

Answer & Step-by-step explanation:

It is less because 2 times 3/4 is the same as 2/1 times 3/4 which is 6/4 then simplify it and you get 3/2 which then is 1 1/2.

That is why 2 times 3/4 is less than 2.

Hope that helps ;)

7 0

3 years ago

1/3 1/4 3/8 7/24 5/12 which is the biggest

Sati [7]

Answer: 5/12

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Uh, no rush ill give brainliest to the best answer..

Liula [17]

Hey there! :)

Answer:

The 2nd choice.

Step-by-step explanation:

Looking at the tables, we can eliminate those that do not show an increase, then a decrease in speed.

Table 1:

The speed goes from 45, 43, 41, 42, to 43. This shows a decrease, then an increase. This choice is incorrect.

Table 2:

The speed goes from 45, 47, 49, 48 to 47. This shows an increase, then a decrease. This choice is correct.

Table 3:

The speed goes from 45, 45, 45, 43, to 41. This shows a constant speed, until a final decrease. This choice is incorrect.

Table 4:

In this table, the speed goes from 45, 43, 41, 41 and ends at 41. This shows an initial decrease, then a constant speed. This is incorrect.

Therefore, only table 2 shows an increasing, then decreasing speed.

6 0

3 years ago