If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
Answer:
60
Step-by-step explanation:
<u>Step 1: Solve for x</u>
x + 3x + 2x = 180
6x / 6 = 180 / 6
x = 30
<u>Step 2: Find the measure of angle C</u>
Angle C = 2x
Angle C = 2(30)
Angle C = 60 degrees
Answer: 60
Answer is 5
first you do 1 divided by 5 then you times by 25
7. the formula for octagon is a=2(1+radical2)s^2
s=4
a=about 77.25
8.
