Answer:
10y^2-3xy+6x
Step-by-step explanation:
- you will need 2 busses to only transport the boys.
- Mark is at (1 + 5/6) miles of his house.
<h3>How many buses would it take to carry only the boys?</h3>
We know that there are (3 + 1/2) groups, such that each group fill one bus.
2/5 of the students are boys, then the number of groups that we can make only with boys is:
(2/5)*(3 + 1/2) = 6/5 + 1/5 = 7/5 = 5/5 + 2/5 = 1 + 2/5
Then you can make one and a little less than a half of a group, which means that you need 1 and 2/5 of a buss to transport the boys, rounding that to the a whole number, you will need 2 busses to only transport the boys.
<h3>How far is Mark from his house?</h3>
The original distance is:
D = (2 + 3/4) miles.
But Mark only covers 2/3 of that distance, then we have:
d = (2/3)*D = (2/3)*(2 + 3/4) miles = (4/3 + 2/4) miles
d = (4/3 + 1/2) miles = (8/6 + 3/6) miles = (1 + 5/6) miles
Mark is at (1 + 5/6) miles of his house.
If you want to learn more about mixed numbers:
brainly.com/question/21610929
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<span>We are not told how often the interest is compounded, so assuming it is <em /><u><em>compounded yearly</em></u>, you need to keep $9.99 in the account to pay the fee.
<u><em>Explanation: </em></u>
Compound interest follows the formula A=p(1+r)^t,
where:
A is the total amount in the account,
p is the amount of principal,
r is the interest rate as a decimal number,
and t is the number of years.
<u>For our problem: </u>
A = 9.99,
p is unknown,
r = 0.018% = 0.00018,
and t=1.
<u>This gives us: </u>
9.99=p(1+0.00018)^1;
9.99=p(1.00018).
<u>Divide both sides by 1.00018: </u>
9.99=p.</span>
Answer:
I would but its confusing
