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Vlad [161]
2 years ago
15

Which of the following equations has no solutions?

Mathematics
1 answer:
hammer [34]2 years ago
3 0
May. Be D



Am I right
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2) Joanie got paid $111 to babysit three kids for 6 hours. How much was she paid per hour?
Hatshy [7]

Answer:

18.5

Step-by-step explanation:

Since she was paid $111 for 6 hours, you divide 111/6 to get 18.5

6 0
2 years ago
In Lexie's art bag there are 11 green colored pencils, 7 blue colored pencils, and 3 red colored pencils. What is the ration of
melamori03 [73]

Answer: 11:7

Step-by-step explanation:

Number of green colored pencils=11

Number of blue colored pencils= 7

Number of red colored pencils= 3

Total number of colored pencils= 11+7+3= 21

Ratio of green colored pencils to blue colored pencils= 11:7

7 0
3 years ago
13) Circle O is shown with point A, B, C, and D on Circle O.
sladkih [1.3K]

The value of y is 50

The angle measurement of angle AOB is 100°

<h3>Circle Geometry </h3>

From the question, we are to determine the value of y and the measure of angle AOB

From one the circle theorems, we have that

Angles in the <u>same segment</u> are equal

In the given diagram, x° and y° are angles in the same segment

∴ x° = y°

From the given information,

x = 50

∴ y = 50

Hence, the value of y is 50

Also, from another circle theorem,

Angle at the <u>center</u> is twice the angle at the <u>circumference</u>

∴ ∠AOB = 2x° = 2y°

Then,

∠AOB = 2×50°

∠AOB = 100°

Hence, the angle measurement of angle AOB is 100°

Learn more on Circle Geometry here: brainly.com/question/17074363

#SPJ1

7 0
2 years ago
a playground is 750 M long and 250 m broad find the cost of levelling at rupees 16 per 100 square metres​
barxatty [35]

Answer:

Area of play ground = Length × Breadth = 750 × 250 = 187500. a Cost of levelling the ground = 187500 × 16 100 = Rs . 30000 

4 0
2 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
Read 2 more answers
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