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butalik [34]
3 years ago
8

Halfway through a bus route, 23 students have been dropped off and 48 students remain on the bus. How many students were on the

bus at the beginning of the trip?
Mathematics
2 answers:
olasank [31]3 years ago
6 0

Answer:

71

Step-by-step explanation:

23 + 48 You just add the number of kids.

wlad13 [49]3 years ago
5 0

Answer:

71 students

Step-by-step explanation:

If 48 students remain on the bus and 23 had been dropped off, all we have to do is add 48 + 23 and then you'll get the answer as of how many kids were in the beginning.

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√48a^4 b^5 c^3 d simplify and keep it in radical form
Morgarella [4.7K]
I will assume the square root extends all the way across.

\sqrt{48a^4b^5c^3}

\sqrt{2^4\cdot3\cdot a^4b^5c^3}

\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}

4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}

\boxed{4a^2b^2c\sqrt{3bc}}






3 0
3 years ago
Please help me? step by step:) ty
Illusion [34]

Answer:

multiply 5 x 4 = 20

multiply the dimensions of the lighter square

after all the multiplying you subtract your answers and you should get the VERY final answer

*don't add because it's area; just multiply

4 0
3 years ago
John has 13 boxes of apples. Each box holds 6 apples. If 7 of the boxes are full, and 6 of the boxes are half full, how many app
TEA [102]
John would have 60 apples!
Hope this helps!!!!! And btw tell John to give me some of them apples lol XD
7 0
3 years ago
Determine the most specific name for the figure in the diagram.
Makovka662 [10]
<span>ABCD is a parallelogram. Looking at the quadrilateral ABCD, the first thing to do is to determine if the opposite sides are parallel to each other. So let's check that by looking at the opposite sides. Line segment BA. When you go from point B to point A, you move to the right 1 space, and down 4 spaces. So the slope is -4. Looking at line segment CD, you also move to the right 1 space and down 4 spaces, which also means a slope of -4. So those two sides are parallel. When you compare line segments BC and AD, you'll notice that for both of them, you go to the right 5 spaces and up 2 spaces, so those too are parallel. So we can now saw that the quadrilateral ABCD is a parallelogram. Since ABCD is a parallelogram, we now need to check if it's a rectangle (we know it can't be a square since the sides aren't all the same length). An easy way to test if it's a rectangle is to check of one of the angles is 90 degrees. And if we draw a line from B to D, we can create a triangle ABD. And in a right triangle, due to Pythagora's theorem we know that A^2 + B^2 = C^2 where A is the line segment AB, B is the line segment AD and C is the line segment BD. So let's calculate A^2, B^2, and C^2. A^2: Line segment AB. We can construct a right triangle with A = 1 and B = 4. So C^2 = 1^2 + 4^2 = 1 + 16 = 17. So we have an A^2 value of 17 B^2: Line segment AD. We can construct a right triangle with A = 2 and B = 5. So C^2 = 2^2 + 5^2 = 4 + 25 = 29. So we have an B^2 value of 29 C^2: Line segment BD. We can construct a right triangle with A = 2 and B = 6. So C^2 = 2^2 + 6^2 = 4 + 36 = 40. So we have a C^2 value of 40. Now let's check if the equation A^2 + B^2 = C^2 is correct: 17 + 29 = 40 46 = 40 And since 46 isn't equal to 40, that means that ABCD can not be a rectangle. So it's just a parallelogram.</span>
6 0
3 years ago
find the volume of cubical box . if the cost of painting of outer surface is rs 1440 at the rate rs 15 per mcube
bearhunter [10]
Surface of a cubical box=6(side²)

1)We have to calculate the surface of this cubical box.
Rate=cost of painting / surface  ⇒surface=cost of painting/rate

Data:
Rate=$15/m²
cost of painting=$1440

Surface=$1440/($15/m²)=96 m²

2)We find out the length of the side:

Surface of a cubical box=6(side²)

Data:
Surface of a cubical box=96 m2

Therefore:
96m²=6 (side²)
side²=96 m²/6
side²=16 m²
side=√(16 m²)=4 m

3) We find the volume of a cubical box.
volume=(side³)
volume=(4 m)³
volume=64 m³

Answer: the volume of this cubical box would be 64 m³.

3 0
3 years ago
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