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Evgesh-ka [11]
3 years ago
13

Someone help me please I don't get this :\

Mathematics
1 answer:
Mrac [35]3 years ago
7 0
F(x)'s domain is the extent of its x-values and the function x^2 + 3 extends to infinity and negative infinity so its domain is all real #s, 
f(x)'s range is its y-values and f(x) is only defined for and values above 3, so its range is y>= 3

f(x)^-1 is the function  (x-3)^(1/2) which is a square root function and x >= 3 because if x were to be 2 there would be a negative in the square root which means the y-value would be on the imaginary axis. 
the range is y>= 0 because the output of the square root function can never be negative in this context as it is not being multiplied by a negative on the front 
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Gennadij [26K]
We have that
47 ml

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the answer is the option
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It only counts as a zero when the y-intercept is (0,0).

Step-by-step explanation:

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4vir4ik [10]
22 and 27 is the answer. what else do you need??
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Is these correct bro
iren [92.7K]

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yes

Step-by-step explanation:

if my eyes are good then yes

3 0
3 years ago
Help me with this one pls
bagirrra123 [75]

1/3y + 28 = -5

Subtract 28 from both sides:

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y = -99

The answer is E) NOTA

6 0
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Read 2 more answers
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