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3 years ago

Please explain #2 for me please! The question deals with proportions.

Mathematics

1 answer:

Ket [755]3 years ago

3 0

We claim that the ratio of the areas is (3/2)^3=27/8, not just for these lengths, but also for every possible set of side-lengths x, y, and z.

To find the volume of the area of the original suitcase, multiply together x, y, and z to get xyz. The modified suitcase will have all these dimensions multiplied by 1 1/2, or 3/2, for a result of 3x/2*3y/x*3z/2=27xyz/8. The ratio is (27xyz/8)/(xyz)=27/8, as desired.

Note that we made no assumptions about the value of x, y, and z throughout the whole solution! Therefore, we can plug ANY side-lengths, including the problem's set (28, 16, 8) into this problem to achieve the same ratio.

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Solve for x. 9(x + 1) = 25 + x O x= 2 O x = 3 x=4 Ox=5

Arturiano [62]

9x+9=25+x
8x=16
X=2
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3 0

2 years ago

The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All

Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

$Pr(A)=\dfrac{11}{36}$ - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

$Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.$

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

$Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.$

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

$Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.$

4 0

3 years ago

Lowest common multiple of 4 and 10

atroni [7]

Answer: 20

Step-by-step explanation:

2^2=4

5*2=10

2^2 and 5 would be multiplied

8 0

3 years ago

Read 2 more answers

You are given an n×n board, where n is an even integer and 2≤n≤30. For how many such boards is it possible to cover the board wi

faltersainse [42]

Answer:

Step-by-step explanation:

The number of cells in a tile is 4. If colored alternately, there are 3 of one color and 1 of the alternate color. To balance the coloring, an even number of tiles is needed. Hence the board dimensions must be multiples of 4.

In the given range, there are 7 such boards:

4×4, 8×8, 12×12, 16×16, 20×20, 24×24, and 28×28

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3 years ago

How many flat whole cubes would I use to model 1,200

Natalka [10]

You will need one 1,000 box cube and 2 flat ones

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3 years ago