a) C(0.5) = 39,  C(2)  =  39,  C(4)  =  69
b) Answers in part (a) represents the values of C at x = x₀
c) C(x) is continuous at x = 2
C (x) = 39 for 0 ⩽ x ⩽ 2
Since x = 0.5 is in the range 0 ⩽ x ⩽ 2:
C(0.5)  =  39
Since x = 2 is in the range 0 ⩽ x ⩽ 2
C(2)  =  39
Since x = 4 is in the range x  >  2
C(4) = 39 + 15(x - 2)
C(4) = 39  +  15 (4 - 2)
C(4)  =  39  +  15(2)
C(4)  =  39  +  30
C(4)  =  69
b) The answers in part A represents C(x). That is, the values of C at x = x₀
c) Is C(x) continuous at x = 2
C(2)   =  39

Since  , the function C(x) is continuous at x = 2
, the function C(x) is continuous at x = 2
Learn more here: brainly.com/question/20710468
 
        
             
        
        
        
Answer:
A
Step-by-step explanation:
1.9 about 2, and 4.4 is about 4. 
2x4=8
So it is safe to say between 4 and 10. 
 
        
             
        
        
        
Answer:
17.7 cm^2
Step-by-step explanation:
Use trig to find the height of the triangle. Then the area is bh/2.
Extend side BC to the right until it is vertically below point A. Draw a segment from point A vertically down until it intersects the extension of side BC. Call the point of intersection D. <D is a right angle.
Use triangle ABD to find the height, AD, of triangle ABC.
For <B of 37 deg, AD is the opposite leg. AB is the hypotenuse. The trig ratio that relates the opposite lefg to the hypotenuse is the sine.
sin B = opp/hyp
sin 37 deg = AD/13.1
AD = 13.1 * sin 37 deg
AD = 7.9
AD is the height of triangle ABC. BC is the base. We can find the area of triangle ABC.
area = bh/2
area = (4.5 cm)(7.9 cm)/2
area = 17.7 cm^2
 
        
             
        
        
        
Answer:
your really think ik the answer
Step-by-step explanation:
yea the  sorry
 
        
                    
             
        
        
        
So to graph you problem you should first consider that the one side of the bar is 150feet because it is in the other partitioned of the fence and the function of it would be 150(x) because the barn's area is calculated through it length time width. I hope this will help