Option 3:
m∠ABC = 66°
Solution:
Given 
and ABH is a transversal line.
m∠FAB = 48° and m∠ECB = 18°
m∠ECB = m∠HCB = 18°
<u>Property of parallel lines:
</u>
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠FAB = m∠BHC
48° = m∠BHC
m∠BHC = 48°
<u>Exterior angle of a triangle theorem:
</u>
<em>An exterior angle of a triangle is equal to the sum of the opposite interior angles.</em>
m∠ABC = m∠BHC + m∠HCB
m∠ABC = 48° + 18°
m∠ABC = 66°
Option 3 is the correct answer.
Answer:
I have to go so I am not able to write all the answers but you can use the explanation. I tried my best. I hope this helps. Please mark me brainly!
Step-by-step explanation:
To write a perpendicular equation to this one, first, put the equation of the line given into slope-intercept form by solving for y. You get y = -2x +5, so the slope is –2. Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. I hope this helps. Please mark me brainly!
Answer:
3
Step-by-step explanation:
there you go pal :)))))
Answer:
The monthly fee would be $23
Step-by-step explanation:
hope it helps mark as brainllest if help!!!
