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maria [59]
2 years ago
11

Solve for p: A. p = 25 B. p = 20 C. p = 50 D. p = 200

Mathematics
1 answer:
docker41 [41]2 years ago
4 0

Answer:

p=a+2

Step-by-step explanation:

It fax

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In a 650g bag of mixed dried fruits, the ratio of mangos to apples to pears is 12:8:6 by mass. Determine the masses of the mango
Virty [35]

Answer:

mass of mangos = 300g

mass of apples = 200g

mass of pears = 150g

Step-by-step explanation:

lets first reduce the ratio

12:8:6

is the same as

6:4:3

this means the the denominator of our fractions will be 6 + 4 + 3 = 13

hence

mangos = 6/13 of 650g

6/13 * 650 = 300

apples = 4/13 of 650g

4/13 * 650 = 200

pears = 3/13 of 650g

3/13 * 650 = 150

7 0
2 years ago
Answer the question below<br><br> 1 - (-4)
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Answer:

4

Step-by-step explanation:

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3 years ago
What is the range of this equation? f(x) = x + 41 – 2
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3 0
2 years ago
If ABCDE is translated 7 units to the right and 2 units up, what will happen to the polygon?
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 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
2 years ago
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