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Sergeu [11.5K]
3 years ago
15

Find the volume of a pyramid with a square base, where the side length of the base is 6.1\text{ m}6.1 m and the height of the py

ramid is 4.7\text{ m}4.7 m. Round your answer to the nearest tenth of a cubic meter.
Mathematics
1 answer:
Ilya [14]3 years ago
7 0

Answer:

58.3m^3

Step-by-step explanation:

volume of a pyramid = 1/3 x length x width x height

1/3 x (6.1 x 6.1 x 4.7) = 58.3 m^3

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

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Find the sum of 19x3+1(14x+4x3)
Step2247 [10]
Find the sum of 19x3+1(14x+4x) 

The answer is 19x3+4x3=4x.
5 0
3 years ago
Find the value of x if y =1/4x and 5x-8y=33​
Verdich [7]

Answer:

x=11

Step-by-step explanation:

y= 1/4x

5x-8y=33

5x-8(1/4x)=33

x=11

8 0
3 years ago
Which choices are correct when determining the distance between −56 and 69?
Gnesinka [82]

The choices that are correct when determining the distance between −56 and 69 are |-56 - 69| and 125 units

<h3>How to determine the choices that are correct when determining the distance between −56 and 69?</h3>

The endpoints are given as

−56 and 69

The distance between the endpoints is calculated using

Distance = |Difference between  endpoints|

So, we have:

Distance = |-56 - 69|

Evaluate

Distance = 125

Hence, the choices that are correct when determining the distance between −56 and 69 are |-56 - 69| and 125 units

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brainly.com/question/4727909

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6 0
2 years ago
The radius of a circle is 8 feet. What is the area of sector bounded by a 90° arc?
Lera25 [3.4K]

Since 90 degree is 1/4 of a circle, the area will be 1/4 th area of the full circle.

The radius is given by, r = 8 ft, therefore, the area of the full circle is,

\begin{gathered} A=\pi\times r^2 \\ A=3.14\times8^2=200.96ft^2 \end{gathered}

Therefore, the area of the sector is,

A^{\prime}=\frac{1}{4}\times200.96ft^2=50.24ft^2\begin{gathered} A^{\prime}=\frac{\theta}{360}\times\pi\times r^2 \\ \text{ =}\frac{\text{90}}{360}\times\pi\times8^2 \\ \text{ =}\frac{1}{4}\pi\times64=16\pi \end{gathered}

4 0
1 year ago
Solve inequality -8x+4≤36.
BigorU [14]

\bf{-8x+4\leq 36 }

Subtract 4 from both sides.

\bf{-8x\leq 36-4 }

Subtract 4 from 36 to get 32.

\bf{-8x\leq 32 }

Divide both sides by −8. Since −8 is <0, the inequality direction is changed.

\bf{x\geq \dfrac{32}{-8}  }

Divide 32 by −8 to get −4.

\bf{x\geq -4 \ \ \Rightarrow \ \ \ Answer }

<h2>{ Pisces04 }</h2>
4 0
2 years ago
Read 2 more answers
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