Ok. so, you have a fraction. lets say it is, 5/20. and the other, is. 2/5. flip the first one, and multiply. so your answer would be, 25/40. hope this helps.
When using substitution, we are imputing an equation in place of a variable to eliminate one of the variables in the equation so that we can solve for the remaining variable.
For this example, we will be plugging in (-4y+12) wherever "x" is in the other equation.
3/4 x -5y = 7
3/4(-4y+12) -5y =7
((3/4)(-4y))+((3/4)12)-5y=7
-3y+9-5y=7
-8y= -2
y=(1/4)
Now find "x" by plugging in the y-value.
x=(-4*(1/4))+12
x= -1 +12
x=11
any questions? feel free to comment below!
Answer: 30:5
Step-by-step explanation:
Five levels were beaten so thirty levels are left so whats left to what’s beaten is 30:5
Answer:
Step-by-step explanation:
Making more than $150
Let the amount to be made be x.
Then: x+$150 will be the amount needed to be made
Answer: " (3,1) is the point that is halfway between <em>A</em> and <em>B</em>. "
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Explanation:
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We know that there is a "straight line segment" along the y-axis between
"point A" and "point B" ; since, we are given that:
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1) Points A, B, C, and D form a rectangle; AND:
2) We are given the coordinates for each of the 4 (FOUR points); AND:
3) The coordinates of "Point A" (3,4) and "Point B" (3, -2) ; have the same "x-coordinate" value.
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We are asked to find the point that is "half-way" between A and B.
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We know that the x-coordinate of this "half-way" point is three.
We can look at the "y-coordinates" of BOTH "Point A" and "Point B".
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which are "4" and "-2", respectively.
Now, let us determine the MAGNITUDE of the number of points along the "y-axis" between "y = 4" and y = -2 .
The answer is: "6" ; since, from y = -2 to 0 , there are 2 points, or 2 "units" from y = -2 to y = 0 ; then, from y = 0 to y = 4, there are 4 points, or 4 "units".
Adding these together, 2 + 4 = 6 units.
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So, the "half-way" point would be 1/2 of 6 units, or 3 units.
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So, from y = -2 to y = 4 ; we could count 3 units between these points, along the "y-axis". Note, we could count "2" units from "y = -2" to "y = 0".
Then we could count one more unit, for a total of 3 units; from y = 0 to y = 1; and that would be the answer (y-coordinate of the point).
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Alternately, or to check this answer, we could determine the "halfway" point along the "y-axis" from "y = 4" to "y = -2" ; by counting 3 units along the "y-axis" ; starting starting with "y = 4" ; note: 4 - 3 = 1 ; which is the "y-coordinate" of our answer; that is: "y = 1" ; and the same y-coordinate we have from the previous (aforementioned) method above.
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We know the "x-coordinate" is "3" ; so the answer:
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" (3,1) is the point that is halfway between <em>A</em> and<em> B </em>."
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