The answer for the question is 36 , 36
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Answer:
Step-by-step explanation:
Since the question implies his truck travels at a constant distance per gallon, we can set up the following proportion to find how much father his truck can go.
Let 
represent how much farther his truck can go, in kilometers:
Cross-multiplying, we get:
Answer:
C. 20%
Step-by-step explanation:
50*2=100
40*2=80
100-80=20
Answer:
Step-by-step explanation:
sin=y/r
cos=x/r
sin=21/29
cos=x/29
x^2+y^2=r^2
x^2+21^2=29^2
x^2+441=841
x=sqrt(841-441)
x=20
cos=20/29
Only |
sin + | All Positive
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only | Only cos +
tan + |
