Can someone please help me?

What is -4 2/3 as a decimal with work

Luba_88 [7]

The decimal equivalent is -4.666....

In order to find this, we need to start by just taking the whole number for itself.

-4.

Now we have to handle the fraction version. In order to do that, we need to do the division and turn into a decimal.

2/3 = .666...

Now we simply put them together and get our answer.

-4.666...

6 0

3 years ago

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

3 years ago

Divide 48 in the ratio 3 : 6:7

Marina CMI [18]

Answer:

$48 \times \frac{3}{16} \\ 9$

$48 \times \frac{6}{16} \\ 18$

$48 \times \frac{7}{16} \\ 21$

9:18:21

7 0

3 years ago

Read 2 more answers

Given the piecewise function shown below , select all of the statements that are true.

TEA [102]

Shown Where? You didnt add a picture of a graph

4 0

3 years ago

We draw 2 cards from a deck of 52 cards. what is the probability that both are queens?

solniwko [45]

Use combination
There are 4 queen cards in a deck of 52 cards
Probability = 4C2 / 52C2

I calculate 4C2 first
4C2 = 4! / (2! 2!)
4C2 = (4 × 3 × 2 × 1) / (2 × 1 × 2 × 1)
4C2 = 6

Then I calculate 52C2
52C2 = 52! / (50! 2!)
52C2 = (52 × 51)/2
52C2 = 1.326

Hence, the probability is
Probability = 4C2 / 52C2
Probability = 6/1,326
Probability = 1/221

7 0

3 years ago