Answer:
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean of 0.6 times a day
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.
In which
So
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Answer:
5/15 - 2/15
Step-by-step explanation:
Answer:
68in^2
Step-by-step explanation:
I divided the hexagon into 2 trapezoids
area of a trapezoid is t+b/2 h then
t-top or in this case 3
b-base or in this case 7
h-height or in this case 5
angle S = (Angle TR - Angle WX )/2
Replace the known angles:
34 = (93 - Angle WX) /2
Multiply both sides by 2:
68 = 93 - Angle WX
Solve for WX:
WX = 93 - 68
WX = 25
The answer is 25 (:
Answer:
99.9973 %
Step-by-step explanation:
This is a binomial probability distribution.
Since the probability of satisfactory welds = 97% = 0.97 and the probability of defective welds = 3% = 0.03.
Since there are 3 welds and we require at least one being defective, our binomial probability is
P(x ≥ 1) = 1 - P(x ≤ 0) = 1 - P(0) = 1 - ³C₀(0.03)³(0.97)⁰ = 1 - 1 × 0.000027 × 1 = 1 - 0.000027 = 0.999973 × 100% = 99.9973%
