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madreJ [45]
3 years ago
10

Determine the missing angle​

Mathematics
2 answers:
Stella [2.4K]3 years ago
5 0

Answer:

180-77

Step-by-step explanation:

adjacent angles are supp

Gre4nikov [31]3 years ago
3 0

Answer:

103° | See Attached Image

Step-by-step explanation:

The angle opposite of 77° is vertical (it makes an X, therefore the angles are equal.)

The corresponding angle to the vertical of 77° is also equal to 77°.

X is supplementary to the previously mentioned angle, so it adds up to 180°.

180 - 77 = 103°

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Please help with this asap!! Would help a lot for me :)
lisov135 [29]

Answer:

answer 1 = true

answer 2 . Area of shaded part is 87m^2

<em><u>explanation in the pic above</u></em>

3 0
3 years ago
Read 2 more answers
Write the polynomial 8x − 27 + 2x2y − y2 + 7y in standard form.
Westkost [7]
Your answer is 2x^2y-y^2+8x+7y-27
3 0
3 years ago
Slips of paper numbered 1 to 15 are placed in a box. A slip of paper is drawn at random. What is the probability that the number
monitta

Given:

Slips of paper numbered 1 to 15 are placed in a box.

To find:

The probability that the number picked is either a multiple of 5 or an odd number.

Solution:

We have,

Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

No. of total outcomes = 15

Multiple of 5 are 5, 10, 15.

Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.

Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.

No. of favorable outcomes = 9

We know that,

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

\text{Probability}=\dfrac{9}{15}

\text{Probability}=\dfrac{3}{5}

\text{Probability}=0.6

Therefore, the  probability that the number picked is either a multiple of 5 or an odd number is 0.6.

8 0
3 years ago
According to the data released by the Chamber of Commerce of a certain city, the weekly wages of factory workers are normally di
stich3 [128]

Complete question :

a. Of less than$720?

b. Of more than $840?

c. Between $680 and $760?

Answer:

0.500 ; 0.0013 ; 0.6827

Step-by-step explanation:

Given that :

Mean, μ = 720

Standard deviation, σ = 40

P(Z < x)

x = (x < 720)

Obtain the standardized value of x

P(x < 720) = (x - μ) / σ

P(x < 720) = (720 - 720) / 40

P(x < 720) = 0

P(Z < 0) = 0.5

B.) More than $840

P(x > 840)

P(x > 840) = (x - μ) / σ

P(x > 840) = (840 - 720) / 40

P(x > 840) = 120 / 40 = 3

P(Z > 3) = 0.0013499 (Z probability calculator)

c. Between $680 and $760?

P(760 < x < 680)

P(760 < x < 680) = ((x - μ) / σ) - ((x - μ) / σ)

P(760 < x < 680) = ((760 - 720) / 40) - (680 - 720) / 40)) = P( Z < - 1) - P(Z < - 1)

P(680 < x < 760) = 0.84134 - 0.15866 = 0.68268

3 0
3 years ago
In a​ survey, 32​% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result
adoni [48]

Answer:

z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of  pet owners contacted by telephone is NOT significantly lower than 0.32

Step-by-step explanation:

Data given and notation

n=210 represent the random sample taken

X=61 represent the number of pet owners contacted by telephone

\hat p=\frac{61}{210}=0.29 estimated proportion of  pet owners contacted by telephone

p_o=0.32 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportions is lower than 0.32.:  

Null hypothesis:p \geq 0.32  

Alternative hypothesis:p < 0.32  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of  pet owners contacted by telephone is NOT significantly lower than 0.32

3 0
3 years ago
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