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trapecia [35]
2 years ago
14

Which graphs show continuous data?

Mathematics
2 answers:
Ulleksa [173]2 years ago
7 0

Answer:

Ok, ok, I see what's happening here

You're face to face with greatness, and it's strange

You don't even know how you feel

It's adorable

Well, it's nice to see that humans never change

Open your eyes, let's begin

Yes, it's really me, it's Maui

Breathe it in

I know it's a lot

The hair, the bod

When you're staring at a demi-god

What can I say except, "You're welcome"

For the tides, the sun, the sky

Hey, it's okay, it's okay

You're welcome

I'm just an ordinary demi-guy

Hey

What has two thumbs and pulled up the sky

When you were waddling yea high?

This guy

When the nights got cold

Who stole you fire from down below?

You're lookin' at him, yo

Oh, also I lassoed the sun

You're welcome

To stretch your days and bring you fun

Also I harnessed the breeze

You're welcome

To fill your sails and shake your trees

So what can I say except you're welcome

For the islands I pulled from the sea

There's no need to pray, it's okay

You're welcome

Ha, I guess it's just my way of being me

You're welcome

You're welcome

Well, come to think of it

Kid, honestly I could go on and on

I could explain every natural phenomenon

The tide, the grass, the ground

Oh, that was Maui just messing around

I killed an eel

I buried its guts

Sprouted a tree, now you got coconuts

What's the lesson?

What is the take-away?

Don't mess with Maui when he's on a break-away

And the tapestry here on my skin

Is a map of the victories I win

Look where I've been

I make everything happen

Look at that mean mini-Maui just tickety-tappin'

(Ha ha ha ha ha ha, hey)

Well, anyway let me say, "You're welcome" (you're welcome)

For the wonderful world you know

Hey, it's okay, it's okay, you're welcome (you're welcome)

Well, come to think of it, I gotta go (hey)

Hey, it's your day to say, "You're welcome" (you're welcome)

'Cause I'm gonna need that boat

I'm sailing away, away, you're welcome (you're welcome)

'Cause Maui can do anything but float

You're welcome

(You're welcome)

You're welcome

And thank you

Gnom [1K]2 years ago
3 0

Answer:

A B and D

Step-by-step explanation:

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Building and reduce<br><br>1/2 = / 10​
Vladimir [108]

Answer: 5/10

Explanation: Compare the denominators. Since 2 ⋅ 5 = 10, multiply the numerator 1 by 5 to get 5.

7 0
2 years ago
It is given that ∠ABC and ∠CBD are Response area. So, m∠ABC+m∠CBD=90° using the Response area. It is also given that ​m∠ABC=35°​
zhenek [66]

THE QUESTION CAN BE WRITTEN AS THIS;

It is given that ∠ABC and ∠CBD are a____________ So, m∠ABC+m∠CBD=90° using the b____________. It is also given that ​m∠ABC=35°​. Using the substitution property of equality, you have c________+ ​m∠CBD=90°​. Therefore, using the subtraction property of equality, ​m∠CBD=55°

Answer:

a)COMPLIMENTARY ANGLE

b)DEFINITION OF COMPLEMENTARY ANGLES

c)35°+ m<CBD = 90 degrees.

Step by step Explanation:

a)It's given that <ABC and <CBD are (COMPLIMENTARY ANGLE)

We know that the Sum of Complementary angles equal to 90 degrees.Those angles don't have to be next to each other, just so long as the total is 90 degrees. That's why the Sum of m<ABC and m<CBD equals 90 degrees that is m<ABC + m<CBD = 90 degrees

b)using the (DEFINITION OF COMPLEMENTARY ANGLES) It is also given that m<ABC = 35 degrees.

c)Using substitution property of equality, you have (35°+ m<CBD = 90 degrees.)

If we subtract 35 from both sides, we get 35-35+ m<CBD = 90-35.

Therefore, m<CBD = 55 degrees.

PLEASE CHECK THE ATTACHED FIGURE TO SEE HOW THE QUESTION LOOKS LIKE

8 0
3 years ago
For the model to be to scale, the ratio of the height to the side length should be the same for both the actual pyramid and the
Alex787 [66]

Answer: yes it’s close

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Whats the slope between (4,-2) and (12,10)
yKpoI14uk [10]
M=0 The slope is zero
Hope this helps

4 0
3 years ago
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 25/ms. The ball's height h (in meters) aft
Lina20 [59]
Set h =11
11=-5t^2+25t+1
-5t^2+25t-10=0
Now use quadratic formula to solve for t

t=[-b+\-sqrt(b^2-4ac)]/(2a)
t= [-25+\-sqrt((25)^2-4(-5)(-10))]/2(-5)
t= .438sec and 4.562sec
8 0
3 years ago
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