Answer:
8022.
Step-by-step explanation:
Let x be the number of years after 2010.
We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.
We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.
Since we know that an exponential function is in form:
, where,
a = Initial value,
b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.
Let us convert our given decay rate in decimal form.
![6\5=\frac{6}{100}=0.06](https://tex.z-dn.net/?f=6%5C5%3D%5Cfrac%7B6%7D%7B100%7D%3D0.06)
Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:
![y=14,000*(1-0.06)^x](https://tex.z-dn.net/?f=y%3D14%2C000%2A%281-0.06%29%5Ex)
![y=14,000*(0.94)^x](https://tex.z-dn.net/?f=y%3D14%2C000%2A%280.94%29%5Ex)
Let us find x by subtracting 2010 from 2019.
![x=2019-2010=9](https://tex.z-dn.net/?f=x%3D2019-2010%3D9)
Upon substituting x=9 in our function we will get,
![y=14,000*(0.94)^9](https://tex.z-dn.net/?f=y%3D14%2C000%2A%280.94%29%5E9)
![y=14,000*0.5729948022286167](https://tex.z-dn.net/?f=y%3D14%2C000%2A0.5729948022286167)
![y=8021.927\approx 8022](https://tex.z-dn.net/?f=y%3D8021.927%5Capprox%208022)
Therefore, the population of fish in 2019 will be 8022.
Since the remander is 0 the answer is 2x²+5x+2
Answer:
0.8
Step-by-step explanation:
7 is in the tenth place since there is a 5 in the hundreds we round up to 8.
hope this helped =3
17: 900 because 3,000 + 900 + 40 +7 is 3,947 or 3,947-3,000-40-7= 900