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3 years ago

Which statement is true about the given function?

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

Option C.

Step-by-step explanation:

If the graph of a function f(x) lies above the x-axis, then f(x) > 0.

If the graph of a function f(x) lies below the x-axis, then f(x) < 0.

From the given graph it is clear that the graph of f(x) intersect the x-axis at x=3.

Before x=3 the graph lies below the x-axis. So,

$f(x) < 0$ over the interval $(-\infty,3)$ .

After x=3 the graph lies above the x-axis. So,

$f(x) > 0$ over the interval $(3,\infty)$ .

Therefore, the correct option is C.

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The perimeter of the new m-phone is 16 inches. The phones length is 5.25 inches. What is the width of the phone

True [87]

Perimeter is all the sides added up together.
Divide 16 by 2, so that you can get just a measurement of the length and the width.

16/2 = 8

Since the length is 5.25, subtract that by 8.

8-5.25 = 2.75

The width of the phone is 2.75 inches.

5 0

2 years ago

Nate solve the equation 3 times 5 equals 15 by writing and solving 15 divided by 5 is 3 x plane why Nate's method works

Vsevolod [243]

Division is the opposite from multiplication

8 0

3 years ago

Please answer quickly!!!

mixas84 [53]

Answer:

Step-by-step explanation:

5x + 13y = 232

12x + 7y = 218

For each choice:

a) The first equation can be multiplied by –13 and the second equation by 7 to eliminate y. So we have

- 65x - 169y = - 3016

84x + 49y = 1526

Can not eliminate x and y.

b) The first equation can be multiplied by 7 and the second equation by 13 to eliminate y. So we have

35x + 91 y = 1624

156x + 91y = 2834

Can not eliminate x and y if we ADD.

<em>(If we subtract, this is Yes)</em>

c) The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.

-60x - 156y = - 2784

60x + 35y = 1090

The answer is YES

d) The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.

25x + 65y = 1160

144x + 84y = 2616

Can not eliminate x and y

The final answer is C

3 0

3 years ago

Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,

creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

To find : Write out the first 5 terms of this sequence ?

Solution :

$a_n=a_{n-1}+3n-1$ and $a_0=0$

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

$a_1=a_{1-1}+3(1)-1$

$a_1=a_{0}+3-1$

$a_1=0+2$

$a_1=2$

For n=2,

$a_2=a_{2-1}+3(2)-1$

$a_2=a_{1}+6-1$

$a_2=2+5$

$a_2=7$

For n=3,

$a_3=a_{3-1}+3(3)-1$

$a_3=a_{2}+9-1$

$a_3=7+8$

$a_3=15$

For n=4,

$a_4=a_{4-1}+3(4)-1$

$a_4=a_{3}+12-1$

$a_4=15+11$

$a_4=26$

For n=5,

$a_5=a_{5-1}+3(5)-1$

$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

5 0

3 years ago

4 1/3 u^5v^3·(3 1/4 u^3v^2−v^2+u)

QveST [7]

You can go to the app Photomath if you want the step of the explanation

6 0

3 years ago