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2 years ago

I'm taking my final please answer this and wish me luck

Mathematics

2 answers:

Papessa [141]2 years ago

5 0

ANSWER:

Let distance be b.

Using pythagorean theorem,

b² = (25)² - (24)²

b² = 625 - 576

b² = 49

b = √49

b = 7ft.

So, Correct choice - [B] 7 feet.

Tema [17]2 years ago

3 0

Answer:

B 7feet

Step-by-step explanation:

Side a = 24

Side b = 25

Side c = 7

Angle ∠A = 73.74° = 73°44'23" = 1.287 rad

Angle ∠B = 90° = 1.5708 rad = π/2

Angle ∠C = 16.26° = 16°15'37" = 0.28379 rad

C=16.26°B=90°A=73.74°b=25a=24c=7

Area = 84

Perimeter p = 56

Semiperimeter s = 28

Height ha = 7

Height hb = 6.72

Height hc = 24

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What is the nth term rule of the quadratic sequence below?

Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

Given sequence:

6, 20, 40, 66, 98, 136, ...

Calculate the first differences between the terms:

$6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136$

As the first differences are not the same, calculate the second differences:

$14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38$

As the second differences are the same, the sequence is quadratic and will contain an n² term.

The coefficient of the n² term is half of the second difference.

Therefore, the n² term is: 3n²

Compare 3n² with the given sequence:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

The second operations are different, therefore calculate the differences between the second operations:

$3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18$

As the differences are the same, we need to add 5n as the second operation:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2 &-2 & -2 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0

1 year ago

One vertex of a triangle is located at (0, 5) on a coordinate grid. After a transformation, the vertex is located at (5, 0). Whi

madreJ [45]

Answer:

The Transformations are R(O , -90°) & R(O , 270)

Step-by-step explanation:

* Lets revise the rotation of a point

- If point (x , y) rotated about the origin by angle 90° anti-clock wise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clock wise

(270° anti-clockwise or -90°)

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise (-180°) or

anti-clockwise (180°) around the origin

* Lets solve the problem

∵ One vertex of a triangle is located at (0, 5) on a coordinate grid

∵ The image of the point after the transformation is (5 , 0)

- The coordinates are switched with each other

∴ There is no rotation with 180° or -180° because in the rotation with

180° and -180° around the origin we change only the signs of the

coordinates without switch them

∴ There is a rotation with 90° are 270° or -90°

- The zero has no sign

- When we rotate the point (0 , 5) by -90° or 270° around the origin

we will change the sign of x-coordinate and switch the two

coordinates

∴ The image of the point is (y , -x)

∵ x = 0 and y = 5

- There is no sign for zero, so we switch the coordinates only

∴ The vertex is located at (5, 0)

∴ The Transformations are R(O , -90°) & R(O , 270)

3 0

2 years ago

Read 2 more answers

The cost of a ticket to the circus is $14.00 for children and $32.00 for adults. On a certain day, attendance at the circus was

Evgesh-ka [11]

400 children and 600 adults bought tickets.

Step-by-step explanation:

Given,

Cost of one child ticket = $14

Cost of one adult ticket = $32

Total attendance = 1000

Revenue generated = $24800

Let,

x be the number of children.

y be the number of adults.

According to given statement;

x+y=1000 Eqn 1

14x+32y=24800 Eqn 2

Multiplying Eqn 1 by 14

$14(x+y=1000)\\14x+14y=14000\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(14x+32y)-(14x+14y)=24800-14000\\14x+32y-14x-14y=10800\\18y=10800\\$

Dividing both sides by 18

$\frac{18y}{18}=\frac{10800}{18}\\y=600$

Putting y=800 in Eqn 1

$x+600=1000\\x=1000-600\\x=400$

400 children and 600 adults bought tickets.

Keywords: linear equations, subtraction

Learn more about subtraction at:

#LearnwithBrainly

8 0

2 years ago

Jose earned 50 points in a video game. He lost 40 points, earned 87 points, then lost 30 more pints. Write and evaluate an expre

Aneli [31]

50-40+87-30=67

hope i helped

4 0

2 years ago

Identify the zeros of f(x)=(x-3)(x+9)(4x-3)

Arlecino [84]

Answer:

X=3

X=-9

x=3/4

Step-by-step explanation:

3 0

2 years ago