Question

Help I have 10 mins.

Answer 1

Answer:

$\sqrt{0.5}$

Step-by-step explanation:

cosx=adj/hyp

adj= $\sqrt{2}$/2

hyp= r

cos(45)= ($\sqrt{2}$/2)/r

$\sqrt{2}$/2 = ($\sqrt{2}$/2)/r

   multiply both sides by r

($\sqrt{2}$/2)r = $\sqrt{2}$/2

    divide both sides by $\sqrt{2}$/2

r = 1

pythagorean theorem: $a^{2}$ + $b^{2}$ = $c^{2}$

a = $\sqrt{2}$/2

b = y

c = r = 1

$(\sqrt{2}/2)^{2}$ + $y^{2}$ = $1^{2}$

    $(\sqrt{2}/2)^{2}$ = 2/4 = 0.5

0.5 + $y^{2}$ = 1

    subtract 0.5 from 1

$y^{2}$ = 0.5

$\sqrt{y^{2}}$ = $\sqrt{0.5}$

y = $\sqrt{0.5}$