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matrenka [14]
3 years ago
9

The cost of 10 hot dogs at a hot dog stand is $30. Which graph shows the cost of different numbers of hot dogs at the hot dog st

and?
a

The first quadrant of a coordinate grid is drawn. The title is Hot Dog Stand. The horizontal axis label is Number of Hot Dogs, and the scale is from 0 to 8 in increments of 1. The vertical axis label is Cost in dollars, and the scale is from 0 to 48 in increments of 6. Points are plotted at the ordered pairs 1,6 and 2,9 and 3,12.


b

The first quadrant of a coordinate grid is drawn. The title is Hot Dog Stand. The horizontal axis label is Number of Hot Dogs, and the scale is from 0 to 8 in increments of 1. The vertical axis label is Cost in dollars, and the scale is from 0 to 48 in increments of 6. Points are plotted at the ordered pairs 2,6 and 3,6 and 4,6.


c

The first quadrant of a coordinate grid is drawn. The title is Hot Dog Stand. The horizontal axis label is Number of Hot Dogs, and the scale is from 0 to 8 in increments of 1. The vertical axis label is Cost in dollars, and the scale is from 0 to 48 in increments of 6. Points are plotted at the ordered pairs 1,6 and 2,12 and 3,18.


d

The first quadrant of a coordinate grid is drawn. The title is Hot Dog Stand. The horizontal axis label is Number of Hot Dogs, and the scale is from 0 to 8 in increments of 1. The vertical axis label is Cost in dollars, and the scale is from 0 to 48 in increments of 6. Points are plotted at the ordered pairs 2,6 and 4,12 and 6,18.
Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0
The answer is A, Hope this helps
fenix001 [56]3 years ago
4 0

Answer:

30

Step-by-step explanation:

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\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


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then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

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