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lawyer [7]
3 years ago
8

Whats 2+2 please fneviuqba

Mathematics
2 answers:
mr_godi [17]3 years ago
4 0

Answer:

4

Step-by-step explanation:

1+1+1+1=4

2+2=4

2*2=4

Bogdan [553]3 years ago
3 0

Answer:

4

Step-by-step explanation:

two plus two equals four

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At mcdonalds you can order mcnuggets in boxes 6,9, or 20. by ordering 2 boxes of 6 you can get twelve. butyou cant get 13, since
Vinil7 [7]
That would be 19. I belive this bc 9 plus 9 is 19 and no matter what combination of boxes you will not have 19 chiken nugets
8 0
3 years ago
The map ratio of a map is 1: 50000. find the length on the ground represented by 6.4cm on the map
luda_lava [24]

Answer:

320,000

Step-by-step explanation:

6.4cm on the map would be 320,000 (ft I'm assuming) and I found that by multiplying 50,000x6.4.

3 0
3 years ago
What is the distance between the points ( 19, 4) and (11, 12)?
Olenka [21]
D = \sqrt{(x_{2}- x_{1})^{2}+ (y_{2} -y_{1})^{2}}
D = √(11-19)²+(12-4)²
D = √(-8)²+(8)²
D = √64+64
D = √128
D ≈ 11.3137 
8 0
3 years ago
→
Rudiy27
It is 9 degrees because at 6am the temperature was -12 degrees and at 10am the temperature was -3 degrees.
7 0
4 years ago
An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are E(1)= ^9C_2 places in which the other 2 red balls can be placed.

A red ball drawn third, there are E(3)= ^7C_2 places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are E(5)= ^5C_2 places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are E(7)= ^3C_2 places in which the other 2 red balls can be placed.

The total number of total event is S= ^{10}C_3

The probability that A selects the first red ball is

P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}

P(A \text{wins})=\frac{36+21+10+3}{120}

P(A \text{wins})=\frac{70}{120}

P(A \text{wins})=0.5833

6 0
3 years ago
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