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3 years ago

I need an answer for this

Mathematics

2 answers:

Misha Larkins [42]3 years ago

5 0

Answer:

756 cm^2

Step-by-step explanation:

9 x 12 = 108 triangles

9 x 18 = 162 back side

9^2 + 12^2 = c^2

9^2 + 12^2 = 225

9^2 + 12^2 = 15^2

length of the hypotenuse is 15 so

15 x 18 = 270 slanted top

18 x 12 = 216 bottom

216 + 270 + 162 + 108 = 756 cm^2

RUDIKE [14]3 years ago

4 0

Answer:

Step-by-step explanation:

18+12+9

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$g(3)=6$

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1 year ago

There are 5280 feet in one mile how many feet are there in 6 miles

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3 years ago

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3 years ago

Mr Makgato sells his car for R42 000.00. The total commission is 7.2% of the selling price of which the broker receives 2 thirds

astra-53 [7]

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3 years ago

If you have 6 cars, but there is only room in your driveway for 3 cars, in how many ways can you arrange the cars in your drivew

Svetradugi [14.3K]

If the order does not matter, cars can be arranged in 20 ways

If an order is important, cars can be arranged in 120 ways

The probability that the three newest cars end up parked in the driveway is 0.167

1. If the order does not matter, combination is used

$\left ({n} \atop {r}} \right.)=\frac{n!}{r!(n-r)!}$

Here, n=6 r=3

using formula,we get

$\left ( {{6} \atop {3}} \right)=\frac{6!}{3!3!} =5*4=20$

2. If an order is important, Permutation will be applicable

$^{n}P_{r} = \frac{n!}{(n-r)!} \\$

∴ $^{6} P_{3} =\frac{6!}{3!(6-3)!}=\frac{6!}{3!} =120$

3. the probability that the three newest cars end up parked in the driveway

P= $\frac{No. of possible outcomes for 3 cars}{total possibilities}$

= $\frac{6*4*5}{6!}$

= $\frac{120}{720}$

= $\frac{1}{6}$ ≈ 0.167

Hence, If the order does not matter, cars can be arranged in 20 ways

If an order is important, cars can be arranged in 120 ways

The probability that the three newest cars end up parked in the driveway is 0.167

Learn more about probability here brainly.com/question/6077878

#SPJ4

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2 years ago