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2 years ago

Answer this question please and I will give brainliest

Mathematics

1 answer:

erik [133]2 years ago

8 0

Answer:

Jordan

Step-by-step explanation:

Because each person is in debt the one with the least amount of dept will pay less. Think of it like this:

You owe the bank 85 dollars so your account balance is -85 since you owe money

if you were to owe 100 dollars then you owe more money.

Therefore owing 85 dollars is the least amount of money owed in this case

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Ms. Wilson purchased a

snow_lady [41]

Answer: 97.7 in

Step-by-step explanation: The perimeter is another name for circumference. Since we know that the formula for circumference is 2(pi)r, but we only want half of that.

Note that 2r is another way of writing the diameter (d).

In this case, we can use the formula d(pi)/2 + d (we’re adding d because d(pi)/2 will only give us the perimeter of the arch.

38(pi)/2 = 59.66

59.66 + 38 = 97.66

Rounded, that would be 97.7 in

5 0

2 years ago

Write a fraction that is equivalent to 6 divided by 27

faust18 [17]

27/6 because this shows that you are dividing 6 from 27.

5 0

2 years ago

Read 2 more answers

How do i solve 426 to the nearest ten

Dmitry [639]

Youll need to provide more information

4 0

3 years ago

Read 2 more answers

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

2 years ago

What is the slope?

cestrela7 [59]

Answer:

5/6

Step-by-step explanation:

rise over run

50/60= 5/6

7 0

3 years ago