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N76 [4]
4 years ago
12

What is the value of (-14⁰)-2 a -1/196 b 1/196c 0 d 1

Mathematics
1 answer:
natta225 [31]4 years ago
6 0

Answer:

It is -1/196 for those who want the quick answer and not the one below me calling the person dumb which I reported BTW because it is unacceptable.

Step-by-step explanation:

I know i dont work for Brainly but i apologize for the person who was called dumb.

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Find the minimum value of c = 4x + 3y
shutvik [7]

Step-by-step explanation:

C=4x+3y Constraints: x is greater than or equal to 0 2x + 3y is greater than or equal to 6 3x - 2y is less than or equal to 9 x + 5y is less than or equal to 20

8 0
3 years ago
Help please I beg if you can
MAVERICK [17]

Answer:

24.30 Difference, sale price 56.70

Step-by-step explanation:

30% off 81.00 is 56.70

The difference is 24.30

7 0
2 years ago
There are 8 sophomores on the academic team. At the last competition, they each took the math test. Their scores were 82%, 92%,
Sav [38]

Answer:

79%

Step-by-step explanation:

To find the median, you need to arrange the numbers in ascending order. Than pick the middle number. If there are two middle numbers then you add them together and then divide by 2.

3 0
3 years ago
A bus as speed of 20m/s begin to slow at constant acceleration of 8.00m/s2 along a straight line find the average speed for the
MrRissso [65]

Answer:

-20 m/s.

Step-by-step explanation:

The computation of the average speed is shown below:

Given that

The initial velocity of the bus, u = 20 m/s

Aceleration of the bus, -a = 8 m/s²

time of motion, t = 5 s

Now The final velocity of the bus is  

v = u + at

v = 20 + (-8 × 5)

v = 20 - 40

v = -20 m/s.

6 0
3 years ago
AB=25 , BD=4, Solve for the radius?<br> Please help!!!!!
Alex787 [66]

9514 1404 393

Answer:

  r = 14.5

Step-by-step explanation:

AD is the perpendicular bisector of chord EC, so is the diameter of the circle. The radius is half the diameter.

  r = AD/2 = (AB +BD)/2 = (25 +4)/2 = 29/2

  r = 14.5

__

Segments BE and BC are 10 = √(25·4)

4 0
3 years ago
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