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Vadim26 [7]
3 years ago
11

41 is what percent of 20

Mathematics
1 answer:
Sedbober [7]3 years ago
6 0
<span>41% of 20=8.2 i think this is the right answer </span>
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Given the following two statements, is the compound statement valid? p: Two angles are congruent. q: The angles are vertical Com
maw [93]
No, this is not valid.  In the picture below, \angle a is a vertical angle with \angle b.  But \angle a is not \cong \angle b

5 0
3 years ago
What values of a and b would make the equation shown have infinitely many solutions? 3x=ax+b
Wittaler [7]
Infinitely many solutions means that you have the same thing on both sides of the equation no matter what value of x you plug in, right?

We just need both sides to be 3x then, correct?

If a were equal to 3 and b were equal to 0, we'd have

3x = (3)x + 0

Which is essentially 3x = 3x

So that means a = 3 and b = 0 must work!
Let's say x = 5

3(5) = 3(5) + 0

15 = 15 + 0

15 = 15

That means that a = 3 and b = 0 is your final answer :)
7 0
3 years ago
Yuan makes punch by mixing cranberry juice and pineapple juice. For every 3 cups of punch, he uses 2 cups of cranberry juice. Dr
Aleks [24]

Answer:

10 cups of canberry juice

Step-by-step explanation:

Given that  for every 3 cups of punch, he uses 2 cups of cranberry juice.

we need to find the number of canberry juice needed to make 15 cups of punch

3 cup's of punch ---> 2 cups of canberry juice

15 cups's of punch ----> x cups of canberry juice

on cross multiplication we get

3\times x=15\times2

x = 10

Therefore we need 10 cups of canberry juice

6 0
3 years ago
What is the answer to this equation 3x-5=2(2x+5)
djyliett [7]

Answer:

x=-1 1/4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help with this and explain how to do it, I'll give 15 points
MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = \frac{10}{2} = 5 cm

Volume of the outer ball V_{1} = \frac{4}{3}\pi (r)^3

                                         = \frac{4}{3}\pi (5)^3

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball V_{2} = \frac{4}{3}\pi (4)^3

Volume of the metal used in the metallic ball = V_{1}-V_{2}

                                                                           = \frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}

                                                                           = \frac{4}{3}\pi [(5)^3-(4)^3]

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0
3 years ago
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