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2 years ago

-3 raised to the power 0=

Mathematics

1 answer:

son4ous [18]2 years ago

3 0

Given:

The statement is "-3 raised to the power 0".

To find:

The value of the given expression.

Solution:

We know that $a$ raised to the power $b$ can be written as $a^b$ .

Any non zero number raised to the power 0 is always 1. It means,

$a^0=1$ , where $a\neq 0$ .

-3 raised to the power 0 $=(-3)^0$

$=1$

Therefore, the value of the given statement is 1.

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If the divisor is 30, what is the least 3 digit dividend that will give you a remainder of 8?

m_a_m_a [10]

The dividend would be 128 because 128 divided by 30 equals to 4 R 8

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Please answer I’ll make brainliest. I have other questions too that I’ll be posting shortly

liraira [26]

Answer:

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1 year ago

James uses 1/2 of a cup of sugar in his cookies, and Jade uses 3/4 of a cup of sugar in her cookies. Noel takes the sum of the t

lesya692 [45]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Bacteria of species A and species B are kept in a single environment, where they are fed two nutrients. Each day the environment

DiKsa [7]

Answer:

We require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

Step-by-step explanation:

Let n₁ be the population of A required and n₂ be the population of B required.

Now we require 2 units of the first nutrient for species A and one unit of the first nutrient for species B. The total nutrients required by species A is 2n₁ and that by species B is 1n₂ = n₂. So, the total nutrients required by both species A and B is 2n₁ + n₂. Since this equals the quantity of the first nutrient which is 10,560, then 2n₁ + n₂ = 10,560 (1)

Now we require 5 units of the second nutrient for species A and 6 units of the second nutrient for species B. The total nutrients required by species A is 5n₁ and that by species B is 6n₂. So, the total nutrients required by both species A and B is 5n₁ + 6n₂. Since this equals the quantity of the first nutrient which is 31,510, then 5n₁ + 6n₂ = 31,510 (2).

So, we have two simultaneous equations which we would solve to find the populations of A and B which satisfy both equations.

2n₁ + n₂ = 10,560 (1)

5n₁ + 6n₂ = 31,510 (2)

From (1) n₂ = 10,560 - 2n₁ (3)

Substituting equation (3) into (2), we have

5n₁ + 6(10,560 - 2n₁) = 31,510

expanding the brackets, we have

5n₁ + 63,360 - 12n₁ = 31,510

collecting like terms, we have

5n₁ - 12n₁ = 31,510 - 63,360

simplifying, we have

- 7n₁ = -31,850

dividing both sides by -7, we have

n₁ = -31,850/-7

n₁ = 4,550

Substituting n₁ = 4,550 into (3), we have

n₂ = 10,560 - 2(4,550)

n₂ = 10,560 - 9,100

n₂ = 1,460

So, we require 4,550 of species A and 1,460 of species B that can coexist in the environment so that all the nutrients are consumed each day

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1 year ago

Solve for x. X -8 = -11 With step by step explanation or with ur work.

igor_vitrenko [27]

To find:

=> The value of x

=>

$x - 8 = - 11$

Now, we'll move -8 to the other side i.e the RHS side,

which results in the change of it's sign(- converts into +)

=>

$x = - 11 + 8$

Now , we'll add the Numbers

=>

$x = - 3$

<h2>Hence,-3 is the required answer.</h2>

^-^

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2 years ago

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