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bixtya [17]
2 years ago
13

-3 raised to the power 0=

Mathematics
1 answer:
son4ous [18]2 years ago
3 0

Given:

The statement is "-3 raised to the power 0".

To find:

The value of the given expression.

Solution:

We know that a raised to the power b can be written as a^b.

Any non zero number raised to the power 0 is always 1. It means,

a^0=1, where a\neq 0.

-3 raised to the power 0 =(-3)^0

                                         =1

Therefore, the value of the given statement is 1.

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You're trying to find constants a_0,a_1,a_2 such that \hat y=a_0+a_1\hat x+a_2{\hat x}^2. Equivalently, you're looking for the least-square solution to the following matrix equation.


\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}

To solve \mathbf{Ax}=\mathbf b, multiply both sides by the transpose of \mathbf A, which introduces an invertible square matrix on the LHS.

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8 0
3 years ago
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