Answer:
L=6x^2-4x+5
P=12x^2-4x-2
Step-by-step explanation:
A=WL
So, we know the area is 6x^2-8x-30 and the width is 2x-6
Substitute
(6x^2-8x-30)=(2x-6)(L)
L=(6x^2-8x-30)/(2x-6
Divide
L=6x^2-4x+5
P=2L+2W
Substitute
P=2(6x^2-4x+5)+2(2x-6)
P=12×^2-8x+10+4x-12
Simplify
P=12x^2-4x-2
Answer:

Step-by-step explanation:
Let
L ----> the length of the rectangular garden in feet
w ---> the width of the rectangular garden in feet
step 1
Find the width
we know that
The perimeter of the rectangular garden is


so

Simplify
----> equation A
----> equation B
substitute equation B in equation A and solve for W
Find the value of L

step 2
Find the area
we know that
The area of the rectangular garden is

substitute the values

I believe that f(2) is 34.5
f(2) = 2(34) + 1
f(2) = 68 + 1
f(2) = 69
f = 69/2
f = 34.5
I AM NOT SURE
Answer:
10f-30g
Step-by-step explanation:
we have:
5(2f - 6g)
we apply distributive property:
5(2f - 6g)
5*2f+5*(-6g)
finally we have:
10f-30g