the congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle. the pe
rimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle. what is the length of the shortest side of the triangle? cm
Let x units be the length of the shortest side of the triangle. Perimeter of triangle = 2(x + 1) +x = 3x + 2 Perimeter of square = 4(x - 2) = 4x - 8 Equating the two expressions for perimeters, we get: 3x + 2 = 4x - 8 The solution is: x = 10