Question

the congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle. the perimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle. what is the length of the shortest side of the triangle? cm

Answer 1

Let x units be the length of the shortest side of the triangle.
Perimeter of triangle = 2(x + 1) +x = 3x + 2
Perimeter of square = 4(x - 2) = 4x - 8
Equating the two expressions for perimeters, we get:
3x + 2 = 4x - 8
The solution is: x = 10

The answer is 10 units.

Answer 2

Answer: The answer is: 10 units

Step-by-step explanation: