the congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle. the pe
rimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle. what is the length of the shortest side of the triangle? cm
Let x units be the length of the shortest side of the triangle. Perimeter of triangle = 2(x + 1) +x = 3x + 2 Perimeter of square = 4(x - 2) = 4x - 8 Equating the two expressions for perimeters, we get: 3x + 2 = 4x - 8 The solution is: x = 10
If your install Bratleby on your device, It will help you with this. But you will have to put in an email. and it will give 10 questions to answer for free. Sorry that I cannot help you with this.
