To maintain pressure within plant cells and keep structure while growth ensues. Good luck, milady. *Tips his fedora*
There always has to be a dominant allele
-The number of B cells producing the antibody is proportional to the concentration of that antibody.
-On day 16, one out of 100000 B cells are specific for antigen A
\frac{1}{100000} = 1 x 10⁻⁵ B cells
- on day 16, Antibody concentration is 2 × 10¹= 20 Antibodies
- on day 36, antibody concentration 8 × 10³.= 8000
20 antibodies ------------ 1 x 10⁻⁵ B cells
8000 antibodies--------------x
x= (8000 x 1 x 10⁻⁵)/ 20
x= 4x10⁻³ or 1 in 250 are <span>B cells specific for antigen A</span>
I think the correct answer from the choices listed above is the first option. The circumstances that this condition would manifest would be if the child is a male and its mother has the recessive allele. X-linked recessive inheritance<span> is a mode of </span>inheritance<span> in which a </span>mutation<span> in a </span>gene<span> on the </span>X chromosome<span> causes the phenotype to be expressed in males </span><span>and in females who are homozygous for the gene mutation</span>
