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wel
2 years ago
15

Instructions: Determine whether the following polygons are similar. If yes, type in

Mathematics
1 answer:
Anni [7]2 years ago
8 0

Answer:

No, the polygons aren't similar since they don't have a constant scale factor.

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Gianna has a two $3,000 one year CDs at different banks. Each compounds
sertanlavr [38]

Answer:

Option D

Step-by-step explanation:

To calculate compound interest we will use the formula :

A=P(1+\frac{r}{n})^{nt}

Where,

A = Amount on maturity

P = Principal amount = $3000

r = rate of interest = 8.4% = 0.084

n = number of compounding period = Monthly = 12

t = time = 1 year

Now put the values in the formula.

A=3000(1+\frac{0.08}{12})^{(12)(1)}

   = 3000(1+0.007)^{12}

   = 3000(1.007)¹²

   = 3000 × 1.08731066

   = 3261.93198 ≈ $3261.93

While the other bank compounds interest daily.

Therefore, n = 365

Now put the values in the formula with n = 365

=3000(1+\frac{0.084}{365})^{(365)(1)}

=3000(1+0.00023014)^{365}

=3000(1.00023014)^{365}

= 3000 × 1.08761958

= 3262.85874 ≈ $3262.86

Difference in the ending balance = 3262.86 - 3261.93

                                                       = $0.93

The difference in the ending balances of both CDs after one year would be $0.93.

8 0
3 years ago
What is the volume of a cylinder, in cubic m, with a height of 6m and a base diameter
natulia [17]

Answer:V= 1526.8m3

Step-by-step explanation: pi (9)2(6)

7 0
2 years ago
find the zeros of 2x^2 - 16x + 27 using the quadratic formula. be sure to simplify the expression. Can someone please show me ho
____ [38]
For a quadratic of the form f(x)=ax^2+bx+c, we have the quadratic formula 
x=\dfrac{-b \pm \sqrt{b^2 -4ac}  }{2a},
where a is the coefficient (number before the variable) of the squared term, b is the coefficient of the linear term, and c is the constant term.

So, given 2x^2-16x+27=0, we can get that a=2, \ b=-16, and c=27. We substitute these numbers into the quadratic formula above.

x=\dfrac{-(-16) \pm \sqrt{(-16)^2 -4(2)(27)} }{2(2)}

x=\dfrac{16 \pm \sqrt{(256 -216)} }{4}

x=\dfrac{16 \pm \sqrt{40} }{4}

x=\dfrac{16 \pm 2\sqrt{10} }{4}

x=4+ \frac{\sqrt{10}}{2}, \ x=4- \frac{\sqrt{10}}{2}

This is our final answer.

If you've never seen the quadratic formula, you can derive it by completing the square for the general form of a quadratic. Note that the \pm symbol (read: plus or minus) represents the two possible distinct solutions, except for zero under the radical, which gives only one solution.
8 0
3 years ago
Guys help me!<br><br> 1. What is the domain and range? Help plsss!
Valentin [98]
Range is the highest value minus the lowest value
6 0
3 years ago
Is x=1 a solution to the equation 8x-2 =16-6x? How do u know
lesantik [10]

Answer:

8x-2=16-6x

No because 16-6x is 10

and 8-2 is 6

5 0
3 years ago
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