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1 year ago

9

The probability of Jane wins a game is 7/10. Jane plays a game 50 times. Find the number of times she is expected to win the gam

e.

1 answer:

viktelen [127]1 year ago

3 0

Answer:

35 times

Step-by-step explanation:

7/10 * 50 = 35

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F(x)=2x+3/4x+5<br>find f(-9)<br>

mylen [45]

$\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}$

$\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}$

$f(x) = \frac{2x + 3}{4x + 5} \\$

For $f(-9)$ , put " $-9$ " for every value of " $x$ ".

$↬f( - 9) = \frac{2( - 9) + 3}{4( - 9) + 5}\\$

$↬ f(-9) = \frac{ - 18 + 3}{ - 36 + 5} \\$

$↬ f(-9) = \frac{ - 15}{ - 31}\\$

$↬ f(-9)= \frac{15}{31}\\$

$↬f(-9)= 0.48\\$

$\bold{ \green{ \star{ \red{Mystique35}}}}⋆$

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