Answer:
option C 13.5%
Step-by-step explanation:
As the heights of adults is normally distributed with mean=69 and standard deviation=2.5 so, the percent of men that are between 64 and 66.5 inches tall can be calculated as
P(64<X<66.5)=P[ (64-69)/2.5<(X-μ)/σ<(66.5-69)/2.5]
P(64<X<66.5)=P(-2<Z<-1)
P(64<X<66.5)=P(-2<Z<0)-P(-1<Z<0)
P(64<X<66.5)=0.4772-0.3413=0.1359
Thus, the percent of men are between 64 and 66.5 inches tall is 13.59%.
If we round the resultant quantity then it will be rounded to 13.6% but considering the given options, option C is most appropriate.
Side lengths: RS=7 and ST=7, and angle=90 degrees
Why?
Since second coordinates of R and S are the same so we can just count the length by adding first coordinate of R and first coordinate of S= |-3|+4=7
Since first coordinates of R is the same as first coordinate of T so we can just count the length by adding second coordinates of S and T=5+|-2|=7
Angle: RST is =90 degrees because triangle RST is right angled triangle. Why? Because RS is parallel to X axis(the same second coordinates of R and S) and ST is parallel to Y axis(the same coordinates of S and T) .
Question:
A sample of cans of peaches was taken from a warehouse, and the content of each can mearsed for weight. the sample means was 486g with stand deviation 6g. state the weight percentage of cans with weight:
Draw normal curve to help - split into 8 section ( i can't draw it here)
a) 34.13% of cans will be between 480g and 486g.
b) 13.59 + 2.15 + 0.13= 15.87% of cans greater than 492g.
Look at the Stand Dev Graph where the give you the number
Step-by-step explanation:
Let me give you a different question and i will answer it, which you help you answer your question.
Evaluate alternatives and select a solution. Hope this helps
